The sum of all the interior angles of a quadrilateral is 360 degrees. If it had more than three obtuse angles, then it would have all four angles greater than 90 degrees so that their sum would be greater than 360 degrees.
If you accept that the sum of the angles in a triangle is 180 degrees, then picture this. A quadrilateral shape is two triangles. If you draw a line between one pair of opposite corners in quadrilateral shape, you have two triangles that share a common side. The sum of the angles in the quadrilateral must equal the sum of the angles in the two triangles. 2 x 180 = 360
The quadrilateral with angles measuring 110°, 100°, 80°, and 70° is a concave quadrilateral. This is because the sum of the interior angles is 360°, which is a property of all quadrilaterals. However, the angles provided do not form a convex shape, as the angles are not in a specific order to create a convex quadrilateral.
The sum of the interior angles of a quadrilateral is 360 degrees. If three of the angles are right angles, that is, of 90 degrees each, the the fourth must be 90 degrees. So you can have a quadrilateral with three right angles but its fourth angle will also be a right angle. So exactly 3 right angles is not possible.
The sum of all four interior angles in a quadrilateral must be 360, so the answer would be: 360 - 54 - 25 - 99 = 182
The sum of the interior angles of a quadrilateral is 360 degrees
A rhombus is a quadrilateral, so the sum of its interior angles is 360o.
There's no such thing as a "triangle quadrilateral".The sum of the interior angles of a triangle is 180 degrees,and for a quadrilateral it's 360 degrees.
Interior angles of any quadrilateral always total 360o.
The sum of the interior angles of a quadrilateral is 360 degrees.
No, the interior angles of a triangle sum to 180o The interior angles of a quadrilateral sum to 360o.
The sum of the 4 interior angles of any quadrilateral add up to 360 degrees.
The sum of the interior angles is 360 Degrees or 2 Pi Radians.
Well a Rhombus is a quadrilateral like a square or a rectangle, and the sum of the interior angles of all quadrilaterals is 360 degrees. So the sum of the interior angles of a rhombus is 360 degrees.
The sum of the 4 interior angles of any quadrilateral add up to 360 degrees.
I'm not sure if you mean interior or exterior angles, so I'll give you an answer for both.For interior angles:The sum of the measures of the *interior* angles of a quadrilateral is always 360 degrees. To understand why this is true, recall that the sum of the interior angles of a triangle is 180 degrees. Now, in any quadrilateral, we can draw a diagonal, splitting it into two triangles.So, the sum of the interior angles of the quadrilateral will be the sum of all of the interior angles of the two triangles, in other words, 2x180.In general, an n-gon can be divided into n-2 triangles, so the sum of the interior angles of an n-gon is 180x(n - 2) = 180xn - 360For exterior angles:The sum of the exterior angles of any closed, convex figure will be 360 degrees. So, if the quadrilateral is convex (isn't bent inwards) the sum of the exterior angles will be 360 as well.
360