180x(N-2)(interior angle)
All polygon of the sums of exterior angles is 360. (if convex)
A polygon that has a sum of 2520 degrees of interior angles has 16 sides
The easiest way to solve this is to use the exterior angles of the polygon. The sum of an exterior angle and interior angle is 180o. Also the sum of all the exterior angles of a polygon is 360o. As the polygon is regular, all the interior angles are the same and all the exterior angles are the same. So, for an interior angle of 172o the exterior angle is 180-172 = 8o. The sum of all the exterior angles is 360o so how many 8o make up 360o? 360/8=45. Thus the polygon with interior angles of 172o has 45 sides.
The sum of the interior angles of a polygon with n sides is 180o × (n - 2), consequently the sum of the interior angles of a 28-sided polygon is 4680o (180o × 26).
A polygon with 50 sides, given the sum of all the interior angles in 8640.
This has to do with the way in which the sum of the angles is derived. First you select a point inside the polygon and then join that point to each of the vertices. For a polygon with n sides, this gives rise to n triangles. The sum of the 3 angles of any triangle is 180 degrees. So the sum of the angles of all the triangles is n*180 degrees. Now, the "outer" angles of these triangles correspond to the interior angles of the polygon. But the sum also includes the angles formed arounf the central point. The sum of all the angles around this central point is 360 degrees. This is not part of the sum of the interior angles of the polygon and so must be subtracted. Thus, the interior angles of a polygon sum to n*180 - 360 degrees or 180*(n- 2) degrees.
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
The sum of the exterior angles of all polygons equals to 360⁰.Since only the sum of the interior angles of all quadrilaterals equals to 360⁰, the polygon must have 4 sides.
A Regular Polygon
A triangle
(number of sides-2)*180 = sum of interior angles of a polygon
the sum of the interior angles of a 3 sided polygon is = 180 degrees. the sum of the interior angles of any polygon is given by 540/n. in this case n is = 3
(number of sides-2)*180+360 = total sum of interior and exterior angles of any polygon.
The sum of the interior angles of an n-sided polygon is 180n - 360 degrees.
(number of sides-2)*180 = sum of the interior angles
The sum of all the interior angles of a polygon with n sides is (n-2)*180 degrees.
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
It is: (n-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon