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Oh, what a happy little question! To find the sum of the first 500 multiples of 3, we can use the formula for the sum of an arithmetic series: (n/2) * (first term + last term). In this case, the first term is 3 and the last term is 3 * 500. Plugging these values in, we get (500/2) * (3 + 1500) = 250 * 1503 = 375,750.
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What is the sum of the first 25 multiples of 3?
975
What is the sum of the first 3 multiples of 10?
10+20+30 = 60
How do you find the first 50 even multiples of 3?
The first 50 multiples of 6 are the first fifty even multiples of 3.
What is the sum of the first 500 odd numbers?
1 + 3 + 5 + .... + 995 + 997 + 999 = 250000
The first 5 multiples of 3?
The first 5 multiples of 3 are as follows: 3, 6, 9, 12, 15
What is the sum of all the multiples of 3 and 5 below 500?
The sum of all multiples of 3 below 500 is the sum of 3 + 6 + ... + 498 = 41583The sum of all multiples of 5 below 500 is the sum of 5 + 10 + ... + 495 = 24750Depending upon the interpretation of "of 3 and 5", the answer is one of:The sum of all multiples of both 3 and 5 below 500 is the sum of 15 + 30 + ... + 495 = 8415The sum of all multiples of 3 below 500 and all multiples of 5 below 500 is 41583 + 24750 = 66333Since the multiples of both 3 and 5 (that is 15, 30, ...) have been counted twice - once in the multiples of 3 and once in the multiples of 5 - the sum of all multiples of 3 or 5 or both below 500 is 41583 + 24750 - 8415 = 57918I have emphasised the word below with regard to 500 since 500 is a multiple of 5, but 500 is not below (less than) itself, that is the multiples are of the numbers 1, 2, 3, ..., 499. If the question was intended to mean less than or equal to 500, add an extra 500 to the multiples of 5 above, making the sum of the multiples of 5 be 25250 and the final sums (1) 8415, (2) 66833, (3) 58418.
What is the sum of the first 10 multiples of 3?
The sum of the first 10 multiples of 3 is 165.
What is the sum of the first 25 multiples of 3?
975
How many multiples of 3 are there between 100 and 500?
There are 166 multiples in 500 (500/3=166r2)and 33 multiples in100(100/3=33 r1) if you subtract the later from the first.... 166-33=133
What is the sum of the first 500 numbers?
The sum of the first 500 positive integers is: 1 + 2 + 3 + ... + 498 + 499 + 500 = 125250
What is the sum of the first 4 multiples of 5?
5 + 10+15+20=50 ans
What is the sum of the first 88 positive multiples of 3?
Sum_ap = ½ × number_of_terms × (first_term + last_term) For the first 88 multiples of three: number_of_terms = 88 first_term = 1 × 3 = 3 last_term = 88 × 3 = 264 → Sum = ½ × 88 × (3 + 264) = 44 × 267 = 11748
What is the sum of the first 3 multiples of4?
4 + 8 + 12 = 24
What is the sum of the first 3 multiples of 10?
10+20+30 = 60
What is the sum of the first 25 multiples of 4?
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
Is 500 one of the multiples of 3?
No. To be divisible by 3, if the sum of the digits is divisible by 3 so is the original number, otherwise the remainder when the sum is divided by 3 is the remainder when the original number is divided by 3. 5 + 0 + 0 = 5 5 ÷ 3 = 1 r 2, so 500 ÷ 3 has remainder 2.
What is the sum of the first 15 multiples of 3?
3+6+9...+45taking 3 common3(1+2+...+15) = 360
