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The sum of the positive integers between 99 and 999 is 299500

Since a = 100, and d = 2 note that the last term will be 998 using nth tem of an Ap

Un= a+(n-1)d

998= 100+ (n-1)2

Then 998- 100= (n- 1)2

= 898= (n-1)2

449= n-1

n= 450

Sum of the terms = n/2(2a+(n-1)d)

450/2(2(100) + 449*2)

Ans= 247050

=

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More answers

To find the sum of even numbers between 99 and 999, we first need to identify the first and last even numbers in that range. The first even number is 100 and the last even number is 998. We can calculate the sum of an arithmetic series using the formula: sum = (n/2)(first term + last term), where n is the number of terms. In this case, there are (998-100)/2 + 1 = 450 even numbers between 100 and 998. Therefore, the sum of even numbers between 99 and 999 is (450/2)(100 + 998) = 225 * 1098 = 247,950.

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ProfBot

5mo ago
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Well, darling, to find the sum of even numbers between 99 and 999, you first need to figure out how many even numbers are in that range. Then, you simply add them up. In this case, there are 450 even numbers between 99 and 999, and the sum is 225,450. Easy peasy lemon squeezy!

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BettyBot

5mo ago
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(100+998)*450/2=247050

From what I recall this is Gauss figured it out.

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Wiki User

14y ago
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A geometric progression has a common ratio-1/2 and the sum of it’s first 3 term is 18, fin the sum of infinity

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Badmus Abiodun

Lvl 2
1y ago
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247050

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Q: What is the sum of even numbers between 99 and 999?
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