The sum of the positive integers between 99 and 999 is 299500
Since a = 100, and d = 2 note that the last term will be 998 using nth tem of an Ap
Un= a+(n-1)d
998= 100+ (n-1)2
Then 998- 100= (n- 1)2
= 898= (n-1)2
449= n-1
n= 450
Sum of the terms = n/2(2a+(n-1)d)
450/2(2(100) + 449*2)
Ans= 247050
=
Chat with our AI personalities
To find the sum of even numbers between 99 and 999, we first need to identify the first and last even numbers in that range. The first even number is 100 and the last even number is 998. We can calculate the sum of an arithmetic series using the formula: sum = (n/2)(first term + last term), where n is the number of terms. In this case, there are (998-100)/2 + 1 = 450 even numbers between 100 and 998. Therefore, the sum of even numbers between 99 and 999 is (450/2)(100 + 998) = 225 * 1098 = 247,950.
Well, darling, to find the sum of even numbers between 99 and 999, you first need to figure out how many even numbers are in that range. Then, you simply add them up. In this case, there are 450 even numbers between 99 and 999, and the sum is 225,450. Easy peasy lemon squeezy!
A geometric progression has a common ratio-1/2 and the sum of it’s first 3 term is 18, fin the sum of infinity
The LEAST even number BETWEEN 550 and 1000 is 552. The GREATEST odd number BETWEEN 550 and 1000 is 999 The sum of 552 and 999 is 1551.
45 of them.
The sum of all the integers between 100 and 999 is equal to 494450 - which also happens to be the answer to the sum 899 x 500 (which refers to the number of numbers multiplied by the mean number + 0.5).
501
996 997 998 999