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The sum of all numbers between 1 and n = n*(n+1)/2

The sum of all numbers between 1 and 999 = 999*1000/2 = 499500

The sum of all numbers between 1 and 9999 = 9999*10000/2 = 49995000

So, the sum of all numbers between 1000 and 9999 = 49495500

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Q: What the sum of all 4 digit number except 0?
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