S = 955
This is an arithmetic sequence, and the sum of an arithmetic sequence can be calculated as:
S = n/2 x (U1 + Un)
U1 is the first term (in this case 91) and Un is the last term (in this case 100).
n presents the total number of terms in the sequence
There are 10 numbers in this sequence (91, 92, 93, 94, 95, 96, 97, 98, 99, 100)
So, the sum is : S = 10/2 x (91+100) = 955
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Two consecutive numbers which add up to 91 are the numbers one half either-side of 91/2 = 45.5. Therefore, the numbers are 45 + 46 = 91.
There are nine(9) numbers: 19, 28, 37, 46, 55, 64, 73, 82, 91
-89, -90, -91, -92
13 and 7
91