0
S = 955
This is an arithmetic sequence, and the sum of an arithmetic sequence can be calculated as:
S = n/2 x (U1 + Un)
U1 is the first term (in this case 91) and Un is the last term (in this case 100).
n presents the total number of terms in the sequence
There are 10 numbers in this sequence (91, 92, 93, 94, 95, 96, 97, 98, 99, 100)
So, the sum is : S = 10/2 x (91+100) = 955
What else can I help you with?
The sum of two consecutive number is 91 What are the numbers?
Two consecutive numbers which add up to 91 are the numbers one half either-side of 91/2 = 45.5. Therefore, the numbers are 45 + 46 = 91.
How many numbers less than 100 have digits whose sum is 10?
There are nine(9) numbers: 19, 28, 37, 46, 55, 64, 73, 82, 91
Find for consecutive numbers with the sum of -362?
-89, -90, -91, -92
What are the factor numbers with the sum of 20 and the product of 91?
13 and 7
What is the sum of all the numbers from 1-90?
91
What two numbers equal 182?
Two numbers that equal 182 can be 91 and 91, since 91 + 91 = 182. Alternatively, you could also have 100 and 82, as 100 + 82 = 182. There are many pairs of numbers that can sum to 182.
What is the sum of 14 in whole numbers?
The sum of the first 14 in whole numbers is 91.
The sum of three consecutive numbers is 276 What are the smallest of these numbers?
91 are.
Two consecutive numbers shave a sum of 91 What are the numbers?
The numbers are 45 and 46.
What is the sum of all composite numbers between 90 and 100?
Add them up. 90, 91, 92, 93, 94, 95, 96, 98, 99, 100
The sum of two consecutive number is 91 What are the numbers?
Two consecutive numbers which add up to 91 are the numbers one half either-side of 91/2 = 45.5. Therefore, the numbers are 45 + 46 = 91.
How many numbers less than 100 have digits whose sum is 10?
There are nine(9) numbers: 19, 28, 37, 46, 55, 64, 73, 82, 91
What is the average of first 91 natural numbers?
The average of the first 91 natural numbers can be calculated using the formula for the average of the first ( n ) natural numbers, which is given by ( \text{Average} = \frac{n(n + 1)}{2n} ). For ( n = 91 ), the sum of the first 91 natural numbers is ( \frac{91 \times 92}{2} = 4186 ). Dividing this sum by 91 gives an average of ( \frac{4186}{91} = 46 ). Therefore, the average of the first 91 natural numbers is 46.
How do you write 91 hundredths in numbers?
It is: 91/100 as a fraction or 0.91 as a decimal
Find for consecutive numbers with the sum of -362?
-89, -90, -91, -92
What are the numbersif the sum of two consecutive number is 91?
The two consecutive numbers are 45 and 46. 45 + 46 = 91.
What are all the composite numbers from 91 to 100?
91, 92, 93, 94, 95, 96, 98, 99, 100
