S = 955
This is an arithmetic sequence, and the sum of an arithmetic sequence can be calculated as:
S = n/2 x (U1 + Un)
U1 is the first term (in this case 91) and Un is the last term (in this case 100).
n presents the total number of terms in the sequence
There are 10 numbers in this sequence (91, 92, 93, 94, 95, 96, 97, 98, 99, 100)
So, the sum is : S = 10/2 x (91+100) = 955
Two consecutive numbers which add up to 91 are the numbers one half either-side of 91/2 = 45.5. Therefore, the numbers are 45 + 46 = 91.
There are nine(9) numbers: 19, 28, 37, 46, 55, 64, 73, 82, 91
-89, -90, -91, -92
13 and 7
91
The sum of the first 14 in whole numbers is 91.
91 are.
The numbers are 45 and 46.
Add them up. 90, 91, 92, 93, 94, 95, 96, 98, 99, 100
Two consecutive numbers which add up to 91 are the numbers one half either-side of 91/2 = 45.5. Therefore, the numbers are 45 + 46 = 91.
There are nine(9) numbers: 19, 28, 37, 46, 55, 64, 73, 82, 91
It is: 91/100 as a fraction or 0.91 as a decimal
-89, -90, -91, -92
The two consecutive numbers are 45 and 46. 45 + 46 = 91.
91, 92, 93, 94, 95, 96, 98, 99, 100
13 and 7
The numbers are -95, -93, and -91.