The sum of the first 14 in whole numbers is 91.
They are 9 and 5
The sum of two numbers is a whole number if both of the numbers are whole numbers, or if the sum of two fractions can be simplified to a whole number.
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
The sum of whole numbers 1 through 30 is 465.
The sum of the first five whole numbers is 10.
What to whole numbers have a sum of 12 and quotient of 3?
the product of 3 whole numbers is 5. Their sum is 7. what are the numbers
The sum of the cubes of the first 100 whole numbers is 25,502,500.
The sum of the first 10 odd whole numbers is 100.
The sum of the whole numbers from 1 to 100 inclusive is 5,050.
You know that sum of the first n whole numbers is n(n+1)/2. ( it is the same as the first n natural numbers since the zero does not add anything) So lets say you want the sum of all the whole numbers between 3 and 10. ( I made it easy to illustrate the idea.) The sum of the whole numbers between 0 and 3 is 3(4)/2=6 The sum of the whole numbers between 0 and 10 is 10(11)/2=55 So the sum of the whole numbers between 3 and 10 is the (sum of the whole number between 0 and 10) -(sum of whole numbers between 0 and 3) which is 55-6=49 So in general, for whole numbers m and n with m
The sum of the first 50 whole numbers is 1,225.