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Using the formula for the sum of an arithmetic sequence;
Sum = 1/2*n [n is the total number of terms] *(2a [a is the value of the first term] + (n-1) * d)[d is the common difference between each term]
So the formula looks like this: Sum = 1/2*n (2a+(n-1)*d)
n = 50 because there's 50 odd numbers in a hundred and 50 even numbers (50+50=100)
a = 1
d = 2
So inputting the values gives:
Sum= 1/2*50 (2*1+(50-1)* 2)
Sum= 25*(2+49*2)
Sum= 25*(2+98)
Sum= 25*(100)
Sum= 2500
Answer= 2,500
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What is the sum from all the odd numbers from 1 to 100?
The sum of all the odd numbers from 1 through 100 is 10,000
The sum of the first positive 100 odd numbers?
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)
What is the sum of the odd numbers from 1-99?
100
What five odd numbers add up to 100?
No 5 odd numbers add up to 100. The sum of any two odd numbers is even. The sum of any two even numbers is even. So the sum of any 4 odd numbers must be even. Take that and add an odd number and the sum must be odd. Therefore, the sum of any 5 odd numbers must be odd. 100 is even. In conclusion: The sum of any odd number of odd numbers is odd.
What is the sum of all odd numbers from 1 to 12000?
The sum of all the odd numbers between 1 and 12000 is 36000000.
