The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
The sum of the first 10 counting numbers (1-10) is 51.
16 and 35
Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550
I believe here are 51 such numbers.
240
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
51
The sum of the first 10 counting numbers (1-10) is 51.
1 and 50 = 51 2 and 49 = 51 3 and 48 = 51 etc There are 25 such pairs, each adding to 51. So the sum is 25*51 = 1275
A sum has to include two or more numbers in the calculation.
50 and 52 are the even numbers in this range, the odd numbers will be all the others, which is just the number 51.
printf ("%d", 51*350);
51 + 57 = 108
16 and 35
The sum of the four given numbers is -13.
Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550