20*(20+1)/2 = 210
The sum of the first 20 integers is 190.
There are 20.
Two of them. Two of them. Two of them. Two of them.
The integers 2 and 10 have a product of 20 and a sum of 12.
First integer divisible by 10 is 10 itself .So the numbers are 10,20,30,40 and so onthe sum is10+20+30+40+....+990+100010(1+2+3+4+.....+99+100)10*100*101/250500
The sum of the first 20 integers is 190.
The sum of the first four non-negative, consecutive, even integers is 20.
There are 20.
The sum of all integers from 1 to 20 inclusive is 210.
Many people would consider 0 to be the first even positive integer, however similar to the neutron in an atom, 0 holds a neutral position. Meaning it is neither a proton (+1) or electron (-1). So our first positive even integer would be 2.2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 = 110, which is the sum of the first ten evenly positive integers.
Two of them. Two of them. Two of them. Two of them.
The integers are 18 and 20.
The integers 2 and 10 have a product of 20 and a sum of 12.
The integers are 19, 20 and 21.
20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22
20+6
The numbers are -22, -21 and -20.