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What is the sum of the first 20 integers is?
The sum of the first 20 integers is 190.
How many positive integers less than 100 have the sum of their digits equal to a perfect square?
There are 20.
How many positive integers less than 20 are equal to the sum of a positive multiple of 3 and 4?
Two of them. Two of them. Two of them. Two of them.
What is the sum of the series of the first 20 positive integers ending in 3?
You can list them out and add them up: 3 + 13 + ... + 193 {20 items}, or you can recognize the sequence: (n = 0..19) of (n*10 + 3), the sum would be 20*3 + 10*Sum[(n=0..19) of just n], which is 20*3 + 10*[190] = 60 + 1900 = 1960. If you add up the column of numbers, you get the same result.
Product of 20 and a sum of 12?
The integers 2 and 10 have a product of 20 and a sum of 12.
What is the sum of the first 20 integers is?
The sum of the first 20 integers is 190.
What is the sum of the first four non-negative consecutive even integers?
The sum of the first four non-negative, consecutive, even integers is 20.
How many positive integers less than 100 have the sum of their digits equal to a perfect square?
There are 20.
What is the sum of all integers from 1 to 20?
The sum of all integers from 1 to 20 inclusive is 210.
What is the sum of first 10 positive even integers?
Many people would consider 0 to be the first even positive integer, however similar to the neutron in an atom, 0 holds a neutral position. Meaning it is neither a proton (+1) or electron (-1). So our first positive even integer would be 2.2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 = 110, which is the sum of the first ten evenly positive integers.
What are the last two digits in the sum of factorials of the first 100 positive numbers?
To find the last two digits of the sum of the factorials of the first 100 positive integers, we can observe that for ( n \geq 10 ), ( n! ) ends with at least two zeros due to the factors of 10 in the factorial (from the pairs of 2 and 5). Therefore, we only need to calculate the sum of the factorials from 1! to 9!. The sum ( 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! ) equals 40320, and the last two digits are 20. Thus, the last two digits in the sum of factorials of the first 100 positive integers are 20.
How many positive integers less than 20 are equal to the sum of a positive multiple of 3 and 4?
Two of them. Two of them. Two of them. Two of them.
The sum of two consecutive even integers is 38 what are the integers?
The integers are 18 and 20.
What is the sum of the series of the first 20 positive integers ending in 3?
You can list them out and add them up: 3 + 13 + ... + 193 {20 items}, or you can recognize the sequence: (n = 0..19) of (n*10 + 3), the sum would be 20*3 + 10*Sum[(n=0..19) of just n], which is 20*3 + 10*[190] = 60 + 1900 = 1960. If you add up the column of numbers, you get the same result.
Product of 20 and a sum of 12?
The integers 2 and 10 have a product of 20 and a sum of 12.
The sum of three consecutive integers is 63?
20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22
Find three consecutive integers whose sum is 60?
The integers are 19, 20 and 21.
