To find the sum of the series of the first 20 positive integers ending in 3, we first need to identify the pattern. The series would be 3, 13, 23, 33, ..., 193. This is an arithmetic series with a common difference of 10. To find the sum, we can use the formula for the sum of an arithmetic series: n/2 * (first term + last term), where n is the number of terms. Plugging in the values, we get 20/2 * (3 + 193) = 10 * 196 = 1960. Therefore, the sum of the series is 1960.
When the quotient of two integers is positive, either both integers are positive or both negative. When the quotient of two integers is negative, one of the integers is positive and one negative. When the quotient of two integers is zero, the first integer is zero and the second one is anything but zero.
105625
They total 650. * * * * * It is 2550.
It is 40*41/2 = 820
50%
The sum of the first 500 positive integers is: 125,250
The sum of the first 30 positive integers is: 465.
The sum of the first ten positive integers is: 55
The sum of the first 60 positive integers is 1830.
The sum of the first 200 positive integers is 19,900.
The sum of the first forty positive integers can be calculated using the formula for the sum of an arithmetic series, which is (n/2)(first term + last term) where n is the number of terms. In this case, the sum is (40/2)(1 + 40) = 820.
The sum of the first eleven positive odd integers is 121.
The first odd positive integers are "1" and "3" which the sum is 4.
The sum of the first 2,006 positive, odd integers is 4,024,036.
The sum of the first thousand even, positive integers is 1,001,000.
The first four positive integers of 13 are : 26, 39, 52, 65
The sum of the first 40 even positive integers can be equal to 820.