It is 46.
The sum of the first five whole numbers is 10.
1+1+1+1+1+=5 * * * * * The question did not ask for the sum of the first counting number five times! The sum of the first 5 counting numbers is 1+2+3+4+5 = 15. Such sums are known as triangular numbers.
the answer is of course 12
There are an many triangular numbers that are also square numbers. Simply put, the sum of two consecutive triangular number equals a square number. Examples include 1 and 36.
That can't be solved. The sum of five odd numbers will always be an odd number.That can't be solved. The sum of five odd numbers will always be an odd number.That can't be solved. The sum of five odd numbers will always be an odd number.That can't be solved. The sum of five odd numbers will always be an odd number.
The sum of the first n cubed numbers is the square of the nth triangular number.
The sum of the first five whole numbers is 10.
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The first five prime numbers are 2, 3, 5, 7, 11. The sum of these five numbers is 28.
1+1+1+1+1+=5 * * * * * The question did not ask for the sum of the first counting number five times! The sum of the first 5 counting numbers is 1+2+3+4+5 = 15. Such sums are known as triangular numbers.
The sum of the first five prime numbers is 28. The sum of the cubes of the first three prime numbers is 160. The average of 28 and 160 is 94.
The first five prime numbers are 2,3,5,7,11. The sum of the first five prime numbers is 28.The sum is: 2+3+5+7+11 = 28
1+3+6+10 =20
If that's the first five, the sum is 28.
the answer is of course 12
The sum of the first 500 even numbers, excluding zero, is 250,500.
When you add two consecutive triangular numbers, the result is a perfect square. For example, the first two triangular numbers are 1 (T1) and 3 (T2), and their sum is 4, which is (2^2). In general, the sum of the (n)-th triangular number (T_n) and the ((n+1))-th triangular number (T_{n+1}) equals ((n+1)^2). This relationship holds for all pairs of consecutive triangular numbers.