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The sum of the first n cubed numbers is the square of the nth triangular number.
The answer is the 100th triangular number so you can use the formula (n(n+1))/2.n = 100 so the sum is (100 x 101)/2 = 10100/2 = 5,050.
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
1+3+6+10 =20
This is very easy. Simply square the number: 100 squared (100 x 100) = 10,000. So, the sum of the first 100 odd numbers is 10,000.