Q: What is the answer to the sum of the first 100 triangular numbers?

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The sum of the first n cubed numbers is the square of the nth triangular number.

The answer is the 100th triangular number so you can use the formula (n(n+1))/2.n = 100 so the sum is (100 x 101)/2 = 10100/2 = 5,050.

The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.

1+3+6+10 =20

This is very easy. Simply square the number: 100 squared (100 x 100) = 10,000. So, the sum of the first 100 odd numbers is 10,000.

Related questions

It is 46.

The sum of the first n cubed numbers is the square of the nth triangular number.

The sum of the first 100 numbers, excluding zero, is 5,001.

The sum of the first 100 odd numbers is 10,000.

The answer is the 100th triangular number so you can use the formula (n(n+1))/2.n = 100 so the sum is (100 x 101)/2 = 10100/2 = 5,050.

The sum of the cubes of the first 100 whole numbers is 25,502,500.

The sum of the first 100 positive even numbers is 10,100.

The sum of the first 100 even numbers is 10,100

The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.

The sum of the first 100 natural numbers is 5,001.

The sum of the first 100 prime numbers is 24,133

The sum of all the first 100 even numbers is 10,100.