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(n/2) times (n + 1)

eg for first 6 integers n = 6 and you have 6/2 x 6 + 1 = 3 x 7 = 21 which is correct.

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Q: What is the sum of the first n positive integer?
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Related questions

What is the sum of any integer n and zero?

Integer n.


What are the rules in multiplying integers?

Let's use N to represent any number.N x N = NN x -N = -N-N x -N = NSo the rules are:A positive integer times a positive integer will be a positive integerA positive integer times a negative integer will be a negative integerA negative integer times a negative integer will be a positive integer.


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A rule in terms of n for the sum of the first n odd positive integers is?

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What is the sum of the first forty positive integers?

The sum of the first forty positive integers can be calculated using the formula for the sum of an arithmetic series, which is (n/2)(first term + last term) where n is the number of terms. In this case, the sum is (40/2)(1 + 40) = 820.


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