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(n/2) times (n + 1)

eg for first 6 integers n = 6 and you have 6/2 x 6 + 1 = 3 x 7 = 21 which is correct.

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Q: What is the sum of the first n positive integer?
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What is the sum of any integer n and zero?

The sum of any integer ( n ) and zero is ( n ).


What are the rules in multiplying integers?

Let's use N to represent any number.N x N = NN x -N = -N-N x -N = NSo the rules are:A positive integer times a positive integer will be a positive integerA positive integer times a negative integer will be a negative integerA negative integer times a negative integer will be a positive integer.


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The sum of the first forty positive integers can be calculated using the formula for the sum of an arithmetic series, which is (n/2)(first term + last term) where n is the number of terms. In this case, the sum is (40/2)(1 + 40) = 820.


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