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Earn +20 ptsQ: What is the sum of the first 80 positive integers?
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How can you solve the problem one positive integer is 3 greater than anotherthe sum of the squares of the two integers is 89find the integers?
Let one positive integer be x, so the other is x+3. The sum of the squares of the two integers is 89, so we have:x2 + (x+3)2 = 89x2 + (x2+6x+9) = 892x2 + 6x + 9 = 892x2 + 6x +9 - 89 = 02x2 + 6x - 80 = 0x2 + 3x - 40 = 0(X+8)(x-5)=0x = 5 (the only positive integer)The 2 positive integers are 5 & 8. Squaring both would be 25 & 64, which the sum is 89.
What is the sum of three consecutive integers is 246 find all three integers?
The numbers are 81, 82 and 83. Also, 80, 82 and 84
What number should be added to -65 to get the sum of 15?
80... since -65 is a negative number, adding positive 80 will produce a value of positive 15.
What is the sum of the first 80 consecutive odd numbers?
40 * * * * * The correct answer is 6400.
The sum of two integers is 120 One half the smaller number plus three-fourths the larger number is 80 What is the smaller number?
200
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