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What are two consecutive odd intergers such that their product is 71more than 7 times their sum?
Let the two consecutive odd integers be ( x ) and ( x + 2 ). The product of the integers is ( x(x + 2) ) and their sum is ( x + (x + 2) = 2x + 2 ). The equation based on the problem statement is ( x(x + 2) = 7(2x + 2) + 71 ). Solving this gives ( x^2 + 2x = 14x + 14 + 71 ), leading to ( x^2 - 12x - 85 = 0 ), which factors to ( (x - 17)(x + 5) = 0 ). Thus, the integers are 17 and 19.
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What are two consecutive numbers with the product of 1482?
They are: 38 times 39 = 1482
What are two consecutive numbers with the product of 7310?
They are: 85 times 86 = 7310
What are two consecutive numbers with the product of 9120?
They are: 95 times 96 = 9120
What are the 2 consecutive numbers with the product of 702?
They are 26 times 27 = 702
The product of 2 positive consecutive even integers is 48.?
They are 6 times 8 = 48
What number is three times the product of two consecutive numbers?
0,6,18,36,60,90,126,168, etc
What are two consecutive numbers with the product of 1482?
They are: 38 times 39 = 1482
What are two consecutive numbers with the product of 7310?
They are: 85 times 86 = 7310
What are two consecutive numbers with the product of 9120?
They are: 95 times 96 = 9120
What are the 2 consecutive numbers with the product of 702?
They are 26 times 27 = 702
The product of 2 positive consecutive even integers is 48.?
They are 6 times 8 = 48
What Two consecutive numbers has a product of 4711?
The two consecutive numbers that have a product of 4711 are 68 and 69. This can be determined by solving the equation ( n(n + 1) = 4711 ). When you calculate ( 68 \times 69 ), it equals 4711.
Will the product of 3 consecutive numbers always be even?
Yes because at least one of the consecutive numbers will be even, and if you times anything by an even number, the answer will always be even
What two consecutive odd integers product is 107 more than 6 times its sum?
They are -7 and -5.
Two consecutive odd integers such that their product is 143 more than 5 times their sum?
17 and 19.
Is 93 and 120 and 301 a rectangular numbers?
A rectangular number, also known as a pronic number, is the product of two consecutive integers. To determine if 93, 120, and 301 are rectangular numbers, we can check if they can be expressed as ( n(n+1) ) for some integer ( n ). 93 can be expressed as ( 9 \times 10 ), which is not the product of consecutive integers. 120 can be expressed as ( 10 \times 12 ), which is also not consecutive. 301 cannot be expressed as a product of two consecutive integers either. Therefore, none of these numbers are rectangular numbers.
Name two consecutive prime numbers whose product is 899?
29 and 31 29 times 31 equals 899
