Let the two consecutive odd integers be ( x ) and ( x + 2 ). The product of the integers is ( x(x + 2) ) and their sum is ( x + (x + 2) = 2x + 2 ). The equation based on the problem statement is ( x(x + 2) = 7(2x + 2) + 71 ). Solving this gives ( x^2 + 2x = 14x + 14 + 71 ), leading to ( x^2 - 12x - 85 = 0 ), which factors to ( (x - 17)(x + 5) = 0 ). Thus, the integers are 17 and 19.
They are 26 times 27 = 702
They are: 38 times 39 = 1482
They are: 85 times 86 = 7310
They are: 95 times 96 = 9120
They are 6 times 8 = 48
0,6,18,36,60,90,126,168, etc
They are 26 times 27 = 702
They are: 38 times 39 = 1482
They are: 85 times 86 = 7310
They are: 95 times 96 = 9120
They are 6 times 8 = 48
Yes because at least one of the consecutive numbers will be even, and if you times anything by an even number, the answer will always be even
17 and 19.
They are -7 and -5.
A rectangular number, also known as a pronic number, is the product of two consecutive integers. To determine if 93, 120, and 301 are rectangular numbers, we can check if they can be expressed as ( n(n+1) ) for some integer ( n ). 93 can be expressed as ( 9 \times 10 ), which is not the product of consecutive integers. 120 can be expressed as ( 10 \times 12 ), which is also not consecutive. 301 cannot be expressed as a product of two consecutive integers either. Therefore, none of these numbers are rectangular numbers.
29 and 31 29 times 31 equals 899
The LCM of two consecutive numbers is always the product: 32 times 33=1056 1056=LCM