short answer
26 and 49
long answer
let x = the first number
let y = the second number
x + y = 75
y = 2x - 3
substitute y into the first equation
x + 2x - 3 = 75
3x = 78
x = 26
use the second equation to find y
y = 2(26) - 3
y = 52 - 3
y = 49
Let the numbers be x and y If: x+2y = 3 and 2x+y = 27 Then the simultaneous equations work out as: x = 17 and y = -7
13 and 26
The third number is 112, the numbers are 86, 86, 112, 172
244
122
Let the numbers be x and y If: x+2y = 3 and 2x+y = 27 Then the simultaneous equations work out as: x = 17 and y = -7
13 and 26
The third number is 112, the numbers are 86, 86, 112, 172
the sum of three numbers is 64. the second number is 3 less than the first number, the third number is 11 less than twice the first. what are the three numbers?
244
122
244
Let x represent the first number; 2x - 3 then represents the second number. x + 2x - 3 = 75 3x = 78 x = 26 2x - 3 = 49 So the numbers are 26 and 49.
Number one = x Number two = y Number three = z x + y + z = 26The second number is twice the first. y = 2x The third number is 6 more than the second. z = y + 6 z = 2x + 6 x + 2x + (2x + 6) = 26 5x = 20 x = 4 Number one = 4 Number two = 8 Number three = 14
The two numbers are 10 and 14.
Let the first number be x, the second number be 3x and the third number be 6x-9: x+3x+6x-9 = 101 10x = 101+9 10x = 110 x = 11 So the numbers are: 1st = 11, 2nd = 33 and the 3rd = 57
a=58.4615 b=5.2308 c=41.3076