Q: What is the sum of x and 10?

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x+10=5x=-5

Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3

Sum(X) = 37 Sum(X2) = 289 Var(X) = Sum(X2) - sum(X)2/n = 289 - 37*37/5 = 15.20

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1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.

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What is the sum of 5 and 10 added to the product of 5 and 10

Let the number you are looking for be x. Then 9 + x = 10 + 10. x is 11.

x+10=5x=-5

Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3

Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2

2 x 50 4 x 25 5 x 20 10 x 10

(3 x 3) + (7 x 3) = 10 x 3 = 30

Capacitors in series: (1/Total) = 1/A + 1/B 1/Total = (B + A) / AB Total = AB/(A+B) = (Product)/(Sum), if only twocapacitors in series. We have 4uf and 6 uf. Product = (4 x 6) x 10-12 = 2.4 x 10-11 Sum = (4 + 6) x 10-6 = 1 x 10-5 Product/sum = (2.4 x 10-11) / (1 x 10-5) = 2.4 x 10-6 = 2.4 uf ======================================== Easier:Total = product/sum = (4 x 6) / (4 + 6) = 24/10 = 2.4 uf

Sum(X) = 37 Sum(X2) = 289 Var(X) = Sum(X2) - sum(X)2/n = 289 - 37*37/5 = 15.20

sum -10 to -1 = -55; sum 1 to 2,012 = 2,013 x 1,006 = 2,025,078 total 2,025,023

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