x+10=5x=-5
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Sum(X) = 37 Sum(X2) = 289 Var(X) = Sum(X2) - sum(X)2/n = 289 - 37*37/5 = 15.20
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1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.
x + 10
Well, isn't that a happy little math problem! The product of 0.5 and 10 is simply 5, and the sum is 10.5. Just like painting, math can be a beautiful way to create something new and wonderful. Remember, there are no mistakes in math, just happy little accidents waiting to be solved.
Let the number you are looking for be x. Then 9 + x = 10 + 10. x is 11.
x+10=5x=-5
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
2 x 50 4 x 25 5 x 20 10 x 10
(3 x 3) + (7 x 3) = 10 x 3 = 30
Capacitors in series: (1/Total) = 1/A + 1/B 1/Total = (B + A) / AB Total = AB/(A+B) = (Product)/(Sum), if only twocapacitors in series. We have 4uf and 6 uf. Product = (4 x 6) x 10-12 = 2.4 x 10-11 Sum = (4 + 6) x 10-6 = 1 x 10-5 Product/sum = (2.4 x 10-11) / (1 x 10-5) = 2.4 x 10-6 = 2.4 uf ======================================== Easier:Total = product/sum = (4 x 6) / (4 + 6) = 24/10 = 2.4 uf
Sum(X) = 37 Sum(X2) = 289 Var(X) = Sum(X2) - sum(X)2/n = 289 - 37*37/5 = 15.20
sum -10 to -1 = -55; sum 1 to 2,012 = 2,013 x 1,006 = 2,025,078 total 2,025,023
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