22
25-3n = 22
tn = 2n2 + 3n - 2
123456789 * * * * * The nth term is 3n
What is the 2nd term of 3n-2?
If that's +25, that factors to (3n - 5)(3n - 5) or (3n - 5)2
3n^2 - n + 1
3n + 2n = 25 5n = 25 n = 5
To find the term from the end in the expansion of ( x - 12x^{3n} ), we can first rewrite it as ( x + (-12)x^{3n} ). The expansion of this expression will consist of two terms: ( x ) and ( -12x^{3n} ). The last term, which is the term from the end, is (-12x^{3n}). Therefore, the required term from the end is (-12x^{3n}).
you have answered your own question 19 - 3n
Just plug in 30 for n in 3n-1. The answer is 89.
[ 13n + 25 ] is.
3n(n+1] + 5 is the nth term