25kg
To determine the total cost of 5 kg at 9p per 1 kg, you would multiply the cost per kg by the total weight. In this case, 9p per 1 kg is equivalent to £0.09 per kg. Therefore, the cost of 5 kg at this rate would be £0.09 x 5 = £0.45.
Well, darling, the object with a greater mass of 5 kg will have a greater gravitational potential energy compared to the object with a measly 2 kg. It's simple physics, honey. So, if you're looking to lift something heavy, go for the 5 kg option and show off those muscles!
1/5 kg
density (usually written Rho) is a ratio of mass by volume (Rho = m/Vol)Standart international units are Kg/m3 (cubic meters)1 liter is equivalent to 1dm3 or 1/1000m3 = 0,001 m310 liters are then equivalent to 1/100 m3 = 0,01 m3so density in your case is Rho = 5/0,01 = 500kg/m3You can as well use other units for exemple in your case densitycan also be expressed in kg/L : Rho = 5/10 = 0,5 kg/L
5 kg
When a 12 kg box is attached to a 5 kg weight, the total mass of the system is 17 kg.
To find the total mass of the box and the tins, we need to consider the weight of the box itself, which is 230 grams. If each tin of fruit has a mass rounded to the nearest half kilogram, the total mass of the 10 tins can vary. Assuming each tin weighs between 0.5 kg to 1 kg, the combined mass of the tins would range from 5 kg to 10 kg, plus the 0.23 kg of the box, resulting in a total mass ranging from approximately 5.23 kg to 10.23 kg.
A bag of sugar that weighs 5 kg is a common example of an object that has a mass of 5 kg.
5000 dumb a$$
the mass of five windows is 90kg if you multiply 18 and 5
Find the density of a material that has a mass of 2 kg and a volume of 5 m3.
Density = 10 kg / 5 litres = 2 kg per litre.
5 kg = 5000 grams 5 kg = 11 lbs 5 kg = 176 oz
The acceleration of an object with a mass of 5 kg and a force of 10 N acting on it is 2 m/s2.
25 kg m/s
Momentum P = mass m x velocity v So P = 10 x 5 = 50 kg m s-1
By conservation of momentum, the total momentum before the lunch equals the total momentum after the lunch. Initially, the total momentum is 5 kg * 1 m/s = 5 kg·m/s, as the smaller fish is initially at rest. After the lunch, since momentum is conserved, the larger fish will have a velocity of 0.2 m/s (5 kg·m/s / (5 kg + 1 kg)).