25 KG
16
1/5 kg
density (usually written Rho) is a ratio of mass by volume (Rho = m/Vol)Standart international units are Kg/m3 (cubic meters)1 liter is equivalent to 1dm3 or 1/1000m3 = 0,001 m310 liters are then equivalent to 1/100 m3 = 0,01 m3so density in your case is Rho = 5/0,01 = 500kg/m3You can as well use other units for exemple in your case densitycan also be expressed in kg/L : Rho = 5/10 = 0,5 kg/L
5 kg
5 kg is greater (it is equal to 5000g)
A typical density for milk is 1.03 kg/ liter. Thus, 5 kg = 5/1.03 = 4.854 liters.
5 liters of water would weigh (in practical situations) 5 kg, so the petrol will be 0.72 times the weight of the water. If a substance has a density of 0.72 kg per liter, then to find the total mass, multiply .72 times the number of liters. In this case, the mass is 3.6 kg.
5 kg = 5000 grams 5 kg = 11 lbs 5 kg = 176 oz
the mass of five windows is 90kg if you multiply 18 and 5
Find the density of a material that has a mass of 2 kg and a volume of 5 m3.
Density = 10 kg / 5 litres = 2 kg per litre.
Density = mass / volume : Mass = volume * density : Volume = mass / densityDensity mild steel = 7.85 kg / litreSo >Mass = volume * density5 litres @ 7.85 kg per litre = 39.25 kilogramsAnd >Volume = mass / density5 kilograms / 7.85 = 0.637 litres
25 kg m/s
5 kilograms = 11.02 pounds.The formula to arrive at the answer is:5 kg*2.2046 lbs1 kg=11.02311311 lbs1 kg = 2.2046 lbsso 5 kg = 11.023 lbs
The mass of the ball is 5 kg. 20 N/ 4.0 M s3 = 5 KG.
Mt*g + Mt*a = Ft Mass total * Graviational field strength + Mass total * acceleration = Force Total or F (N) = .5 (kg) * 9.8 (m/s^2) + .5 (kg) * 3.0 (m/s^2) Now solve for force yourself.
1.102 (approx.). Kilogram (kg) is SI unit of mass and Pound is an Imperial unit. To convert from kg to pound multiply kg unit by 2.20462. To convert from pound to kg multiply pound unit by 0.453592.
The first step here is to find the spring constant. Use Hooke's law and the information given about the 3 kg mass: F=kx F=w3kg-mass=m3kg-massg=(3 kg)(9.8 m/s2) (3 kg)(9.8 m/s2)=(.40 m)k k=[(3 kg)(9.8 m/s2)/(.40 m)] Now plug that in (I don't have a calculator handy, and some of the units and numbers there will cancel, so I didn't bother to calculate it out) to Hooke's law for the 5 kg mass: F=kx F=w5kg-mass=m3kg-massg=(5 kg)(9.8 m/s2) (5 kg)(9.8 m/s2)=kx (5 kg)(9.8 m/s2)=[(3 kg)(9.8 m/s2)/(.40 m)]x x=2/3 m The 5 kg mass would stretch the spring two thirds of a meter.