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What is the total mass of the system when a 12 kg box resting on a horizontal frictionless surface is attached to a 5 kg weight?

When a 12 kg box is attached to a 5 kg weight, the total mass of the system is 17 kg.


A box contains 10 tins of fruit each having a mass to the nearest half kg allowing 230g for the box?

To find the total mass of the box and the tins, we need to consider the weight of the box itself, which is 230 grams. If each tin of fruit has a mass rounded to the nearest half kilogram, the total mass of the 10 tins can vary. Assuming each tin weighs between 0.5 kg to 1 kg, the combined mass of the tins would range from 5 kg to 10 kg, plus the 0.23 kg of the box, resulting in a total mass ranging from approximately 5.23 kg to 10.23 kg.


What is an example of an object that is 5 kg?

A bag of sugar that weighs 5 kg is a common example of an object that has a mass of 5 kg.


What does 5 kg g?

5000 dumb a$$


What is the mass of 5 windows in kg?

the mass of five windows is 90kg if you multiply 18 and 5


Find the density of a material that has a mass of 2 kg and a volume of 5 m3?

Find the density of a material that has a mass of 2 kg and a volume of 5 m3.


What is the density of a 10 kg mass that occupies 5 liters?

Density = 10 kg / 5 litres = 2 kg per litre.


What are the following mass values is equal to 5 kilograms?

5 kg = 5000 grams 5 kg = 11 lbs 5 kg = 176 oz


What is the acceleration in kg/s2m of an object with a mass of 5 kg and a force of 10 N acting on it?

The acceleration of an object with a mass of 5 kg and a force of 10 N acting on it is 2 m/s2.


Calculate momentum of a particle having mass 5 kg and velocity 5 ms?

25 kg m/s


What is the momentum of a bike with a mass of 10 kg moving with a speed of 5 ms?

Momentum P = mass m x velocity v So P = 10 x 5 = 50 kg m s-1


If the larger fish has a mass of 5 kg and swims 1 meter per second toward a 1 kg fish what is the velocity of the larger fish immediately after lunch you will neglect the effects of water resistance?

By conservation of momentum, the total momentum before the lunch equals the total momentum after the lunch. Initially, the total momentum is 5 kg * 1 m/s = 5 kg·m/s, as the smaller fish is initially at rest. After the lunch, since momentum is conserved, the larger fish will have a velocity of 0.2 m/s (5 kg·m/s / (5 kg + 1 kg)).