To determine the total cost of 5 kg at 9p per 1 kg, you would multiply the cost per kg by the total weight. In this case, 9p per 1 kg is equivalent to £0.09 per kg. Therefore, the cost of 5 kg at this rate would be £0.09 x 5 = £0.45.
9 x 5 = 45 20 sweets therefore cost 45 pence.
1/5 kg
9p - 5
The d- prefix is deci- which means 1/10 1 kg = 1000 g → 1 g = 1/1000 kg → 1 dg = 1/10 g = 1/10 × 1/1000 kg = 1/10000 kg → 20 dg/ 1 kg = (20 × 1/10000) kg / 1 kg = 20/10000 = 1/500
326.138336 US gallons Density of JP-5 is 0.81 Kg/L 1 mT of JP-5 1 mT = 1000 Kg 1000 Kg of JP-5 1000 Kg / 0.81 Kg/L = 1234.5679 L 1234.5679 L = 326.138336 US gallons
To find the cost of 1 kg when 5 kg costs 9 p (pence), you divide the total cost by the quantity: 9 p ÷ 5 kg = 1.8 p per kg. Therefore, the cost of 1 kg is 1.8 p.
To calculate the cost of 5 kg at a rate of 9 pence per kilogram, multiply 9 pence by 5 kg. This equals 45 pence. Therefore, the cost of 5 kg is 45 pence.
If 1 kg of tomatoes costs 5 CHF, 0.1 kg will cost 1/10th of 5 CHF, so the cost will be 0.5 kg.
8 is the answer . Since half a kg is 500g, 100 g would cost 1/5 as much. 1/5 of 40 is 8.
9 x 5 = 45 20 sweets therefore cost 45 pence.
Evaluate 9p + 33 for p = 5
To determine how much more than 9p two 2s and one 5 are, first calculate the total value of the two 2s and one 5. This equals (2 \times 2 + 5 = 4 + 5 = 9). Now, subtract 9p from 9 to find the difference: (9 - 9p = 9(1 - p)). Therefore, the result depends on the value of p; if p is less than 1, it is positive, and if p is more than 1, it is negative.
$ 5 -$ 15 depending on quality
1/5 kg
At $7.80 a kg, 5 kg would cost $39.
The cost is: 6.7 times 5 = 33.5
15 = 5 +( 9p - 4p) 15 = 5 + 5p 15 - 5= 5 -5 +5p 10 = 5p there for p = 10/5 = 2