The actual width of a six inch board is 5-1/2in.
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You have provided the length and width of the boards but only the width (height) of whatever you wish to board. there is no information on its length and consequently, the question cannot be answered.
You can find the volume. This is 6*72*96 inches cubed, i.e. 41,472 inches cubed. You then need to convert it to weight using density (possibly need to change units to cm3 or m3.
(width + 6) feet, of course!
It is 22 in by 27 in. ------------------------------------------- How it is solved: The rectangle is 5 in longer than its width, so the dimensions can be given in terms of its width: Its dimensions are width by (width+5) In removing 1 inch squares from the corners, he flaps are going to be (width-2) and (width+5-2) = (width-3) long. Thus the box formed will have volume: volume = (width - 2) in × (width + 3) in × 1 in → volume = width² + width - 6 in³ But we are told this is 500 in³; thus: width² + width - 6 in³ = 500 in³ → width ² + width - 506 = 0 → (width + 23)(width - 22) = 0 → width = -23 or 22 As a length cannot be negative, the width must be 22 in which means the original rectangle is 22 in by 22+5 in = 27 in
6 inch or 4 inch if it's a short radius