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What is the value of k when the line y kx plus 1 is a tangent to the curve y2 equals 8x?
Wiki User
∙ 6y ago
If you mean: y = kx +1 and y^2 = 8x
So if: y = kx +1 then y^2 = k^2*x^2 +2kx +1
If: y^2 = 8x then k^2*x^2 +2kx +1 = 8x
Transposing terms: k^2*x^2 +2kx +1 -8x = 0
Using the discriminant: (2k -8)^2 -4*(k^2*1) = 0
Solving the discriminant: k = 2
Wiki User
∙ 6y ago
Wiki User
∙ 6y agok = 2.
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