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What is the equation of the line tangent to the curve y equals cos x at the point x equals pi over 6?
Wiki User
∙ 10y ago
y = 2(x) - (pi/3) + (sqrt(3)/2)
Wiki User
∙ 10y ago
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How do you find the slope of a graph if it is a curve?
You find the slope of the tangent to the curve at the point of interest.
What is the value of c when y equals x plus c is a tangent to the curve y equals 3 -x -5x squared hence finding the point of contact of the line with the curve showing work?
-2
What t-word is define in geometry as a straight line that touches a curve but continues on with crossing it?
A tangent line touches a curve or the circumference of a circle at just one point.
How do you find the tangent of the line at the curve at the point 11 using the equation 3x3 7x2y 7xy2 2y319?
I'm pretty sure that what you're looking for is: Either the slope or the full equationof the line that is tangent to the curve represented by that messy equation, atthe point (1, 1).If that's so, then . . .-- You'd have to start out by knowing where the plus, minus, and 'equals' signsare in the equation.From there, what I would do is:-- Take the implicit first derivative of the equation, and solve it for y' .That gives you the slope of the curve as a function of points (x, y).-- Use it to find the slope of the curve at the point (1, 1).-- You know that the slope of the line that's tangent at that point is thenegative reciprocal of the slope of the curve. Now you have the slope ofthe tangent line. If that's all you need, then you're done. Retreat and declarevictory.-- If you need the equation of the tangent line, that's no problem. You haveits slope AND a point on it ==> (1, 1). Using that info to find the equationof the line is supposed to be a piece o' cake for you by now.=============================Wait. Don't go away.It looks to me as if the equation is3x3 + 7x2y + 7xy2 + 2y3 = 19just because the point (1, 1) is on it.Do not trust anything I say past this point. I have already wasted too much time on this one and I am not going to check my work. But I did differentiate that mess, and I got the following:Slope of the equation at (1, 1) . . . -10/9Slope of the line tangent to the graph at (1, 1) . . . +0.9Equation of the line . . . Y = 0.9x + 0.1Take it for what it's worth, and Good Luck.
An equation of the line tangent to the graph of y equals x3 plus 3x2 plus 2 at its point of inflection is?
(a) y = -3x + 1
What is the definition of a tangent line?
A tangent is a line that just touches a curve at a single point and its gradient equals the rate of change of the curve at that point.
How do you get the tangent line without the graph?
The answer will depend on the context. If the curve in question is a differentiable function then the gradient of the tangent is given by the derivative of the function. The gradient of the tangent at a given point can be evaluated by substituting the coordinate of the point and the equation of the tangent, though that point, is then given by the point-slope equation.
How the slope of a curved line at a point can be found?
The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.
What is the equation to the tangent line to the curve xy plus y2 equals 0 at the point x equals 3 and y equals 0?
y=0. note. this is a very strange "curve". If y=0 then any value of x satisfies the equation, leading to a curve straight along the y axis. For any non-zero value of y the curve simplifies to y = -x. The curve is not differentiable at the origin.
What is the point of contact when the tangent line y equals x plus c touches the curve y equals 3x -x -5x squared?
-2
How do you find the point of tangency?
A tangent is an object, like a line, which touches a curve. The tangent only touches the curve at one point. That point is called the point of tangency. The tangent does not intersect (pass through) the curve.
How do you find the slope of the tangent line to each curve at the given point?
By differentiating the answer and plugging in the x value along the curve, you are finding the exact slope of the curve at that point. In effect, this would be the slope of the tangent line, as a tangent line only intersects another at one point. To find the equation of a tangent line to a curve, use the point slope form (y-y1)=m(x-x1), m being the slope. Use the differential to find the slope and use the point on the curve to plug in for (x1, y1).
Why we draw tangent in newton raphson method?
A line tangent to a curve, at a point, is the closest linear approximation to how the curve is "behaving" near that point. The tangent line is used to estimate values of the curve, near that point.
How do you find the slope of an Indifference curve?
You find the tangent to the curve at the point of interest and then find the slope of the tangent.
What is a point of tangency?
It is the point at which a tangent touches a curve.
How can you write the equation of the tangent line to the curve?
Well if you have found the derivative (slope of the tangent line) of the curve at that point and you know the xy coordinates for that point in the curve then you set it up in y=mx+b format where y is your y-coordinate, x is your x-coordinate and m is your derivative and solve for b
As a curve approaches a maximum point the slope will do what?
The slope of the tangent line at the maximum point of the curve is zero. So we say that as a curve point approaches to the maximum point, the slope of the tangent line at that point approaches to zero.
