[ln(2) + i*pi]/ln(10) if you are referring to log as a base 10 log. ln refers to the
natural logarithm (log base e)
The log of any negative number is imaginary. The formula above is derived from
the relationship:
-1 = ei*pi
since you want log of -2, multiply both sides by 2
-2 = 2*ei*pi
taking natural logarithm of both sides: ln( -2) = ln(2*ei*pi ) = ln(2) + ln(ei*pi )
which reduces to ln(2) + i*pi
If you want log10 then divide both sides by ln(10)
So log10(-2) = ln(-2)/ln(10) = [[ln(2) + i*pi]/ln(10)
x = log (-2) = log10(-2)
10x = -2
Think about the smallest possible number you can put in for x.
10-∞ = ?
10-∞ = 1/10∞
10∞ = ∞
1/∞ = ?
1/∞ = 0
It is impossible to ever get 0 or a negative number because you will never reach infinity.
log(-2) is undefined
log (21.4 ) = 1.4 log(2) = 1.4 (0.30103) = 0.42144 (rounded)
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
You can, instead, find the log of the ratio. Thus: log(A) - log(B) = log(A/B)
the value of log (log4(log4x)))=1 then x=
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
log AB^2 log A+log B+log2
log (21.4 ) = 1.4 log(2) = 1.4 (0.30103) = 0.42144 (rounded)
try ebay
2ⁿ = 20000 → log(2ⁿ) = log(20000) → n log(2) = log(20000) → n = log(20000)/log(2) You can use logs to any base you like as long as you use the same base for each log → n ≈ 14.29
The value of log o is penis
determination of log table value
After n years of 7 percent growth, the value is (1.07)n times the starting value. The answer to the question is the smallest value of n such that (1.07)n >=2 or nlog(1.07)>= log(2) or n >= log(2)/log(1.07) = 10.2 So the GDP will double during the 11th year.
log(21.4) = 1.330413773
log(22) = 1.342422681
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
You can use logrithms.Take your log table.Look for the log value of 2.Now divide that value by 2(you should devide by 2 if you want square root,devide by 3 if you want cubic root).Now take the antilog value.It is equal to square root.
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4