To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.
This is called a Fibonacci Sequence where the two initial (seed) values are 1 and 3, thereafter every term is the sum of the two previous terms. 4 = 3 + 1 7 = 4 + 3 11 = 7 + 4 18 = 11 + 7 29 = 18 + 11 So the next number would be the sum of, 29 + 18 = 47
8 5 4 9 1 7 6 10 3 2 0 This sequence is special because the numbers are in alphabetical order. The Fibonacci sequence is very special and the triangular sequence.
The sequence in the question is NOT an arithmetic sequence. In an arithmetic sequence the difference between each term and its predecessor (the term immediately before) is a constant - including the sign. It is not enough for the difference between two successive terms (in any order) to remain constant. In the above sequence, the difference is -7 for the first two intervals and then changes to +7.
The nth term of the sequence is 3n - 2.
There is the Morris number sequence and the Fibonacci number sequence. The Padovan sequence. The Juggler sequence. I just know the Fibonacci sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144,233,377 Morris number sequence: 1 11 21 1211 111221 312211...
8, if it is the Fibonacci sequence; 7, if it the sequence of non-composite numbers (1 and primes); there are other possible answers.
The next number is 47. After this series gets going, each number is the sum of the two numbers before it. If the first two numbers were zero and 1, this would be the Fibonacci series.
It has two unique properties:1). It is 13, and so it combines in a single term of an infinite series the well-known holyand fortunate characteristics of 7 with the equally well known harmful and satanic badluck of 13.2). Amazingly enough, no matter how far the Fibonacci series is carried out ... even tothe millionth term ... it can be proven mathematically that the wonderful and mystical7th term is the only term that bears the equally mystical value of 13. Truly one of thegreat mysteries of the wonderful and awe-inspiring realm of numbers.
The given sequence (7, 14, 21, 28, 35,....) is an arithmetic sequence where each term increases by 7. The nth term of the given sequence is 7n
This is called a Fibonacci Sequence where the two initial (seed) values are 1 and 3, thereafter every term is the sum of the two previous terms. 4 = 3 + 1 7 = 4 + 3 11 = 7 + 4 18 = 11 + 7 29 = 18 + 11 So the next number would be the sum of, 29 + 18 = 47
every next term is 4 smaller than previous so 7th term = -23
With a few added commas, hyphens, or spaces, those could be the first 7 terms of the Fibonacci Series.
A sequence of seven numbers is a set of numbers arranged in a specific order. Each number in the sequence is called a term. For example, a sequence of seven numbers could be {1, 3, 5, 7, 9, 11, 13}, where each term differs by a constant value of 2. Sequences can follow different patterns, such as arithmetic sequences where each term is found by adding a constant value to the previous term, or geometric sequences where each term is found by multiplying the previous term by a constant value.
7
8 5 4 9 1 7 6 10 3 2 0 This sequence is special because the numbers are in alphabetical order. The Fibonacci sequence is very special and the triangular sequence.
The lucas numbers are a sequence of numbers. They go as 1, 3, 4, 7, 11, 18 etc the sequence is bery similar to the Fibonacci sequence (1, 1, 2, 3, 5, 8, 13)