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You know that cosπ/4 and sinπ/4 both equal 1/root2, so multiplying them gets 1/2.
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The product of five hundredths and a number is 11?
(.05)*x=11 Where x is the number. Solving for x, x=(11/.05) x=220
If x equals 3 What is the value of x?
the value of x is 3
What is the value of 2 x?
That depends what the value of x is.
What is the absolute value of x minus the absolute value of x?
zero. The absolute value of a number is just the positive version of that number, so the absolute value of x is x, and x minus x is zero.
.05 divided by x 1 then x equals?
0.05
What is 1-cosxsinx plus 1 plus cosxsinx?
2
Is sin 2x equals 2 sin x cos x an identity?
YES!!!! Sin(2x) = Sin(x+x') Sin(x+x') = SinxCosx' + CosxSinx' I have put a 'dash' on an 'x' only to show its position in the identity. Both x & x' carry the same value. Hence SinxCosx' + CosxSinx' = Sinx Cos x + Sinx'Cosx => 2SinxCosx
When are y equals sin x and y equals cos x equal?
y=sinx y=cosxsinx=cosx=>sinx/cosx=1=>tanx=1=>x=45oie.. y=sin45=cos45y=1/(square root of 2)
What is the value of the exponent in the scientific notation expressin for 0000083?
0000083 in Scientific Notation = 8.3E-05 x 106
What is the answer to 05 x 003?
05 x 003 = 150.05 x 0.003 = 0.00015
The product of five hundredths and a number is 11?
(.05)*x=11 Where x is the number. Solving for x, x=(11/.05) x=220
When was Soft Light - The X-Files - created?
Soft Light - The X-Files - was created on 1995-05-05.
What is .05 of one million?
1,000,000 x .05 = 50,000
Integral of cosine squared x?
Integral of cos^2x=(1/2)(cosxsinx+x)+CHere is why:Here is one method: use integration by parts and let u=cosx and dv=cosxdxdu=-sinx v=sinxInt(udv)=uv-Int(vdu) so uv=cosx(sinx) and vdu=sinx(-sinx)so we have:Int(cos^2(x)=(cosx)(sinx)+Int(sin^2x)(the (-) became + because of the -sinx, so we add Int(vdu))Now it looks not better because we have sin^2x instead of cos^2x,but sin^2x=1-cos^2x since sin^2x+cos^2x=1So we haveInt(cos^2x)=cosxsinx+Int(1-cos^2x)=cosxsinx+Int(1)-Int(cos^2x)So now add the -Int(cos^2x) on the RHS to the one on the LHS2Int(cos^2x)=cosxsinx+xso Int(cos^2x)=1/2[cosxsinsx+x] and now add the constant!final answerIntegral of cos^2x=(1/2)(cosx sinx + x)+C = x/2 + (1/4)sin 2x + C(because sin x cos x = (1/2)sin 2x)Another method is:Use the half-angle identity, (cos x)^2 = (1/2)(1 + cos 2x). So we have:Int[(cos x)^2 dx] = Int[(1/2)(1 + cos 2x)] dx = (1/2)[[Int(1 dx)] + [Int(cos 2x dx)]]= (1/2)[x + (1/2)sin 2x] + C= x/2 +(1/4)sin 2x + C
Why does -2sinxcosx equal -sin2x?
-4
What does x - y?
In expressions such as "x-y", both "x" and "y" can have any value. The value of "x-y" will depend on what the value of "x" and the value of "y" are.
What is the answer to 25.00 X 05?
25 X 5 = 125.
