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Adolfo Adams

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12y ago

sin2x=sinxcosx+cosxsinx= 2sinxcosx

sin2x*-1=-sin2x

2sinxcosx*-1=-2sinxcosx

-sin2x=-2sinxcosx

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Q: Why does -2sinxcosx equal -sin2x?
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Related questions

What does sin2x - 1 equal?

1


Is sin2x equal to sin2x?

sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!


Can you solve sinx plus cosx equals 0.5?

Start by squaring both sides of the equation to get, (sinx + cosx)2 = 0.25 Simplify the left side to get sin2x + 2sinxcosx + cos2x = 0.25 Using the Pythagorean identity gets 2sinxcosx + 1 = 0.25 2sinxcosx = -0.75 Using the double angle formula gets Sin(2x) = -0.75 Take the arcsin to get 2x = sin-1(-0.75) x = sin-1(-0.75)/2 Now, a scientific calculator can be used to find the solutions.


Does cos2x equal 2cosxsinx?

No; sin2x = 2 cosx sinx


What is cos squared x equal?

1 - sin2x(1+ cos2x)/2


How do you prove one - tan square x divided by one plus tan square xequal to cos two x?

(1 - tan2x)/(1 + tan2x) = (1 - sin2x/cos2x)/(1 + sin2x/cos2x) = (cos2x - sin2x)/(cos2x + sin2x) = (cos2x - sin2x)/1 = (cos2x - sin2x) = cos(2x)


How does sin2x divided by 1-cosx equal 1 plus cosx?

sin2x / (1-cos x) = (1-cos2x) / (1-cos x) = (1-cos x)(1+cos x) / (1-cos x) = (1+cos x) sin2x=1-cos2x as sin2x+cos2x=1 1-cos2x = (1-cos x)(1+cos x) as a2-b2=(a-b)(a+b)


Double angle formula?

sin(2x) = 2sinxcosx


Sin2x - radical 2 cosx equals 0?

Sin2x = radical 2


What value is equivalent to 1 - cosx squared?

sin2x because sin2x + cos2x = 1


How does 1 plus cot squared x equals csc squared x?

The proof of this trig identity relies on the pythagorean trig identity, the most famous trig identity of all time: sin2x + cos2x = 1, or 1 - cos2x = sin2x. 1 + cot2x = csc2x 1 = csc2x - cot2x 1 = 1/sin2x - cos2x/sin2x 1 = (1 - cos2x)/sin2x ...using the pythagorean trig identity... 1 = sin2x/sin2x 1 = 1 So this is less of a proof and more of a verification.


How do you find sin theta when tan theta equals one fourth?

I will note x instead of theta tan(x) = sin(x) / cos(x) = 1/4 sin(x) = cos(x)/4 = ±sqrt(1-sin2x)/4 as cos2x + sin2 x = 1 4 sin(x) = ±sqrt(1-sin2x) 16 sin2x = 1-sin2x 17 sin2x = 1 sin2x = 1/17 sin(x) = ±1/sqrt(17)