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What is the value of k when the line y kx plus 1 is a tangent to the curve y2 equals 8x?
If you mean: y = kx +1 and y^2 = 8x So if: y = kx +1 then y^2 = k^2*x^2 +2kx +1 If: y^2 = 8x then k^2*x^2 +2kx +1 = 8x Transposing terms: k^2*x^2 +2kx +1 -8x = 0 Using the discriminant: (2k -8)^2 -4*(k^2*1) = 0 Solving the discriminant: k = 2
What is 2 divided by 8x as a fraction in the simplest form?
0.25
What is the answer 8x - 1 equals 11?
8x - 1 = 11 8x = 12 x = 12 / 8 or x = 3 / 2.
What is -8x 16?
if its -8x+16=0 x=2 if its -8x-16=0 x=-2 if its -8x=16 x=-2
Factor completely 8x squared plus 6x minus 5?
8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)
What is the value of k when the line y kx plus 1 is a tangent to the curve y2 equals 8x?
If you mean: y = kx +1 and y^2 = 8x So if: y = kx +1 then y^2 = k^2*x^2 +2kx +1 If: y^2 = 8x then k^2*x^2 +2kx +1 = 8x Transposing terms: k^2*x^2 +2kx +1 -8x = 0 Using the discriminant: (2k -8)^2 -4*(k^2*1) = 0 Solving the discriminant: k = 2
What does 8x for each value of x mean?
You would multiply that value by 8 for every number. So if x is 2, 8x is 16, if x is 3, 8x would be 18.
A triangle has an area of 36 square feet a base of 8x feet and a height of 4 feet what is the value of x?
Area_triangle = base x height x 1/2 ⇒ 36 = (8x) x 4 x 1/2 ⇒ 8x = 18 ⇒ x = 21/4 (= 2.25)
What is 2 divided by 8x as a fraction in the simplest form?
0.25
What is the answer 8x - 1 equals 11?
8x - 1 = 11 8x = 12 x = 12 / 8 or x = 3 / 2.
8x-1 equals -4x plus 23?
8x-1 = -4x+23 8x+4x = 23+1 12x = 24 x = 2
-8x plus 7 equals -7x-2?
-8x+7 = -7x-2 -8x = -7x-2-7 -8x=-7x-9 -8x+7x=-9 -1x=-9 x=-9/-1 x=9
What is the value of k when the line of y equals kx plus 1 is a tangent to the curve of y squared equals 8x?
If y = kx+1 is a tangent to the curve of y^2 = 8x Then it works out that k has a value of 2 and that x has equal roots of 1/2 -------------------------------------- y = kx + 1 and y² = 8x meet when they are equal, ie (substituting for y): (kx + 1)² = 8x → k²x² + 2kx + 1 = 8x → k²x² +(2k - 8)x + 1 = 0 If y = kx + 1 is tangent to y² = 8x, they meet at one point; this occurs when the above quadratic has a repeated root; which happens when the discriminant b² - 4ac = 0, namely: (2k - 8)² - 4 × k² × 1 = 0 → 4k² - 32k + 64 - 4k² = 0 → 32k = 64 → k = ½
What is x 5x plus 1 plus x-2 equals 8x plus 6?
5x+1+x-2 = 8x+6 5x+x-8x = 6+2-1 -2x = 7 x = -3.5
8x-6 equals 5x find the value of x?
2
What is the value of x in the equation 8x plus -2 equals 10?
3/2
What is the answer to 8(x plus 1)3-2(8x plus 4)?
It is 8x + 16
