(4, -2)
y = ½ (6y = 3)
4y - 6y + 9y = -2Combine like terms on the left side:7y = -2Divide each side by 7:y = -2/7The solution set is: { -2/7 }
3x - 6y = 9, 5x + 4y = -27 6x - 12y = 18, 15x + 12y = -81 21x = -63 x = -3 (3 x -3) = 9 + 6y (-9 - 9)/6 = y y = -3 Check: (5 x -3) + (4 x -3) = -15 -12 = -27 QED
x = 7 - 2y 3x = 21 - 6y 21 - 6y + 2y = 5 21 - 4y = 5 21 - 16 = 5 4y = 16 y = 4 x + 8 = 7 x = -1 Check it. -3 + 8 = 5 -1 + 8 = 7 It checks.
By definition: 4y-2 = 6y+8 4y-6y = 8+2 -2y = 10 y = -5 and by substituting this value into the equation x = -22
-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9
but crack
6y 10+4y subtract 4y from each side 2y 10 divide both sides by 2 y = 5
(4, -2)
6y = 10 + 4ySubtract 4y from each side:2y = 10Divide each side by 2:y = 5
y = ½ (6y = 3)
Algebra4y-4 plus y plus 24 equals 6y plus 20-4YCombine like terms5y+20=2y+20Isolate Y3y=0y=0
3y - 7 + y + 27 = 6y + 20 - 4y Collect terms: 4y + 20 = 2y + 20 Subtract 20 4y = 2y The only way that can happen is if y = 0
26 = -6y + 6 + 2y = -4y + 6 Subtracting 6 from both sides: 20 = -4y Dividing both sides by (-4): -5 = y
10y = 2y - 6y + 7 10y =-4y + 7 10y +4y = 7 14y = 7 y = 1/2 = .5
Two straight lines that intersect.