4y + 10 = 22 4y - 10 - 10 4y=12 4y 4y 4y=3
(4, 8)
Add the two equations and get 4x = 12 so x = 3 and y = -1
It is not one, but they are two perpendicular lines.
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2
x = 4 and y = 0
How do you write 4x plus 4y equals 40 or how do you solve it? You would write it 4x+4y=40 you would solve it for y by subtracting 4x from both sides 4y=40-4x then divide all of that by 4y=40-4x/4 that's if you were graphing i have no idea what you're asking hope that helps if it's not too late.
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
4y + 10 = 22 4y - 10 - 10 4y=12 4y 4y 4y=3
That depends what the value of y is.
(4, -2)
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
4y + 7 = 19 ∴ 4y = 12 ∴ y = 3
4y + 19 = 74y = 7-194y = -124y/4 = -12/4y = -3
4
8x plus 4y equals 5 is 8x + 4y = 5.