It is a quadratic expression and when factored it is: (7x+5)(2x-7)
Since every other number is an odd (starting from 1), we automatically could say x, x + 2, x + 4, x - 2, are the variables. Adding these together and setting it to 160 yields a linear equation:x - 2 + x + x + 2 + x + 4 = 4x + 4 = 1604(x + 1) = 160x + 1 = 40x = 39Now plugging into the variables, we have:x - 2 = 39 - 2 = 37x = 39x + 2 = 39 + 2 = 41x + 4 = 39 + 4 = 43Therefore, {37, 39, 41, 43} is the answer.
In mathematics, the notation .9 bar represents a repeating decimal, where the digit 9 repeats infinitely. To show that .9 bar is equal to 1, we can use the formula for an infinite geometric series: a / (1 - r), where a is the first term and r is the common ratio. In this case, a = .9 and r = .1. Plugging these values into the formula gives us .9 / (1 - .1) = .9 / .9 = 1. Therefore, .9 bar is equal to 1.
39x-6
14x2 - 39x - 35 = (7x + 5)(2x - 7)
3x2-39x-90 = (3x+6)(x-15) when factored
41x
The given terms of the expression can be simplified to -32x-17 and no values of x can be found because it is not an equation.
(2x - 7)(7x + 5)
2x - 3= 9 x=
2 - 39x - 50 = 4 + x -39x - 48 = 4 + x Add 39 x to both sides: -48 = 4 + 40x Subtract 4 from both sides: -52 = 40x Divide both sides by 40: x = -1.3
For x-2x= 3x-43x+1 x-2x= -x and 3x-43x+1 = -40x+1 so -x= -40x+1 subtract -x from both sides 0= -39x +1 -1 = -39x so 1=39x so x=1/39
(7x - 5)(5x - 2)
3x-6y=30 y=34-6x substitute the the value for y from the second equation into the first equation. 3x-6(34-6x)=30 3x-204+36x=30 39x-204=30 39x=234 x=234/39 x=6 Substitute this value of x into equation 2. y=34-6(6) y=34-36 y=-2
-38y - 39x (Is that what you were asking for?)