A vector of 13 acting on O at an angle of 60 degrees.
Yes. A simple case would be a vector 2a acting at a point in one direction and two vectors, each of magnitude a, acting at the same point in the opposite direction.
VECTOR
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (40 ft × tan 50° × tan 30°)/(tan 50° - tan 30°) ≈ 44.80 ft
l M l l Q____l____ N lO l l l P Let MP & NQ be lines intersecting at O. Then angle MON + angle NOP = 180 degrees (linear pair) Angle MOQ + angle QOP = 180 degrees (linear pair) Adding the equations, Angle MON + Angle NOP + Angle MOQ + Angle QOP = 180 + 180 degrees = 360 degrees. Therefore all angles around O sum upto 360 degrees.
The dent angle of a star polygon is the angle formed by the bent line between two points that form the point angles. I found a PDF that defines the way to calculate that dent angle and checked it out with a know star. It works: For a star polygon with n points and 2n congruent sides and a point angle of A: the dent angle B = (360/n) + A So for an 8 pointed star with a point angle of 20 degrees, the formula says: (360/8) + 20 = 65 degrees Note that if the point angle is 135 degrees it is really no longer a star polygon because the two (otherwise bent) line between each of the 8 point becomes 180 degrees. The above formula also proves that Equally for an 8 pointed star polygon formed by joining each second point (forming two over lapped squares, the resultant dent angle becomes 135 degrees. Again the formula confirms that angle. Two home-runs feels pretty good! The URL reference is: teach.valdosta.edu/plmoch/MATH3162/Spring%202009/11-3.pdf
Resultant
the radius vector; and the vectorial angle the radius vector; and the vectorial angle
Forces acting on a point such that it gives a null vector by vector addition law, then such type of forces are called balanced forces.
An angle is the point where two lines meet. A point on a straight line is an "angle" of 180 degrees, so a point at the end of a line might possibly be termed a 0 degree angle, but if it's only 1 line then there isn't really an angle.
It can be done with any number of them except 1, if they're pointed in theappropriate directions.With any number ' N ' of equal vectors all acting at the same point, their sum iszero (null) if their directions are uniformly distributed and the angle betweeneach adjacent pair is 360/N degrees.-- With two, they have to point in exactly opposite directions.-- With three, they have to be spaced with 120 degrees between adjacent vectors.-- With four, space them 90 degrees apart.etc.
120 degrees. Go mountaineers!
Angle DCE is an angle where point D and E are the ends and point C is where both meet to form an angle. The degrees of the angle can be found with a protractor.
360 degrees
360 degrees
It is an indicator that the angle formed at that point is a right angle (90 degrees).The small square at the crossing point of two perpendicular lines serves to indicate that the two lines indeed form an angle of 90 degrees.
Yes. A simple case would be a vector 2a acting at a point in one direction and two vectors, each of magnitude a, acting at the same point in the opposite direction.
Torque is defined as a measure of how much a force acting on an object causes that object to rotate. The object rotates about an axis, which is called the pivot point. Let the force acting on it is 'F'. The distance from the pivot point to the point where the force acts is called the moment arm, and is denoted by 'r'.Now, torque, τ = r * F = rFsin ѲHence, torque is the cross product between the distance vector (the distance from the pivot point to the point where force is applied) and the force vector, 'a' being the angle between r and F. We are taking cross product because the variables involved are vectors. Note that the distance in this case is a vector.