A vector of 13 acting on O at an angle of 60 degrees.
Yes. A simple case would be a vector 2a acting at a point in one direction and two vectors, each of magnitude a, acting at the same point in the opposite direction.
VECTOR
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (40 ft × tan 50° × tan 30°)/(tan 50° - tan 30°) ≈ 44.80 ft
l M l l Q____l____ N lO l l l P Let MP & NQ be lines intersecting at O. Then angle MON + angle NOP = 180 degrees (linear pair) Angle MOQ + angle QOP = 180 degrees (linear pair) Adding the equations, Angle MON + Angle NOP + Angle MOQ + Angle QOP = 180 + 180 degrees = 360 degrees. Therefore all angles around O sum upto 360 degrees.
The dent angle of a star polygon is the angle formed by the bent line between two points that form the point angles. I found a PDF that defines the way to calculate that dent angle and checked it out with a know star. It works: For a star polygon with n points and 2n congruent sides and a point angle of A: the dent angle B = (360/n) + A So for an 8 pointed star with a point angle of 20 degrees, the formula says: (360/8) + 20 = 65 degrees Note that if the point angle is 135 degrees it is really no longer a star polygon because the two (otherwise bent) line between each of the 8 point becomes 180 degrees. The above formula also proves that Equally for an 8 pointed star polygon formed by joining each second point (forming two over lapped squares, the resultant dent angle becomes 135 degrees. Again the formula confirms that angle. Two home-runs feels pretty good! The URL reference is: teach.valdosta.edu/plmoch/MATH3162/Spring%202009/11-3.pdf
Resultant
the radius vector; and the vectorial angle the radius vector; and the vectorial angle
To get a null vector, you need to add at least two equal vectors together. Adding any number of equal vectors will always result in a vector that is parallel to the original vector, but to get a null vector the magnitudes of two equal vectors must cancel each other out.
An angle is the point where two lines meet. A point on a straight line is an "angle" of 180 degrees, so a point at the end of a line might possibly be termed a 0 degree angle, but if it's only 1 line then there isn't really an angle.
360 degrees
360 degrees
120 degrees. Go mountaineers!
It is an indicator that the angle formed at that point is a right angle (90 degrees).The small square at the crossing point of two perpendicular lines serves to indicate that the two lines indeed form an angle of 90 degrees.
199
Yes. A simple case would be a vector 2a acting at a point in one direction and two vectors, each of magnitude a, acting at the same point in the opposite direction.
Placing the arrowhead at the terminal point of a vector indicates the direction in which the vector is acting. Without the arrowhead, the vector would be ambiguous and could be interpreted in multiple directions. The arrowhead helps to clearly define the magnitude and direction of the vector.
No, displacement is a vector quantity that measures the change in position of an object from its initial point to its final point, while resultant is a vector that represents the sum or combination of all individual vectors acting on an object.