x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
If the width is 65 yards, then the two short ends are 65 yards. 2 x 65 = 130. Take that 130 from 316 to get the total length of the two long sides. That gives you 186. Divide that by 2 to get the length of one side, giving you 93 yards.
130-83=47cm
130 minus 83 = 47 cm left
130 ounces is bigger than 8 pounds
Assuming you're talking about a rectangle, 452.
x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
130/4 (4 sides to a rectangle)= 32.5 32.5*32.5=1065.25 square meters (because the largest area of a rectangle is always a ^ ^ square). length width
40
P = 130, so L + W = 65. 65 - 2 = 63, 63/3 = 21 m which is the width, making the length 21 + 21 + 2 ie 44 m
A rectangle has only one area - there no smaller or bigger area.
Let the width be x and the length be y So: 2x+2y = 5x implying that y = 1.5x If: xy = 130 and 2/3 Then: x(1.5x) = 130 and 2/3 => 1.5x squared = 130 and 2/3 Divide both sides by 1.5 and then square root both sides: x = 9 and 1/3 cm Length: 130 and 2/3 divided by 9 and 1/3 = 14 cm Therefore: length = 14 cm and width = 9 and 1/3 cm
Insufficient data. Could be anything, assuming width not less than 1 m, from 130 sqm to (32.5 squared) sqm
The perimeter of a rectangle measuring 20x45 centimeters is (2*20) + (2*45) = 40 + 90 = 130 cm
If the width is 65 yards, then the two short ends are 65 yards. 2 x 65 = 130. Take that 130 from 316 to get the total length of the two long sides. That gives you 186. Divide that by 2 to get the length of one side, giving you 93 yards.
Perimeter of a rectanle is the sum of twice the length and twice thewidth. 140 + 140 + 2 x W = 410 2W = 410-280 = 130 W = width = 65 meters
You'd need to know one of the sides.