This cannot have an answer. "7y12" is not correct. If you put a plus before the twelve, this is how you solve it.
y=m(slope)x(independant variable)+b(y intercept)
3x-7y+12
+7y
7y=3x-12
/7 /7 /7
y=3/7+1.714285 repeating
1.714285 repeating is the y intercept
of there is a minus sign, just switch the positive on the y intercept.
It is called the y-intercept and is the constant term in the relevant equation.
from a table to a graph just graph x and y (on a coordinate plane) from table to equation find the slope of the line and the y intercept. your equation should be in the form y=mx+b where m is the slope and b is the y intercept
Assuming the equation is 3x + y = 15, then the x-intercept is (5, 0) and the y-intercept is (0, 15).
The y-intecept is where the graph of the equation crosses the y-axis. In other words, it occurs where x=0. For y=kx, the y-intercept is 0, not k. Substitute 0 for x, and y=0. In an equation of the form y=ax+b, then the y-intercept is b, and the x-intercept is -b/a.
-12
12
The y-intercept of a linear equation is the point where the graph of the line represented by that equation crosses the y-axis.
You can graph a linear equation slope intercept by solving the equation and plugging in the numbers : y=mx+b
-- In the equation of the graph, set x=0. -- Solve the equation for 'y'. -- The value you get for 'y' when x=0 is the y-intercept.
It is called the y-intercept and is the constant term in the relevant equation.
At the x-intercept on the graph of the equation, y=0. Take the equation, set 'y' equal to zero, and solve the equation for 'x'. The number you get is the x-intercept.
At a y-intercept, the graph touches the y-axis, meaning the value of x is 0. So, in any linear equation, simply set x equal to 0 and solve for y. In the slope-intercept form of a linear equation (y = mx + b), the y-intercept value is represented by the variable b.
Assuming the graph is: x = - 305 y, then the y intercept is at y = 0Assuming the graph is: x - 3 = 5y, then the y intercept is at y = -3/5The main point for you to realize here is that a graph represents an equation,and " -305y " is not an equation. So some kind of assumption has to be madein order to come up with something that can be graphed.
If that should be y = 2 the slope is 0 and the y intercept is 2.
1
First write it in the "slope-intercept" form : y = mx + c Then the y-intercept is (0, c)
You can either measure or estimate the coordinates visually from the graph, or solve the equation underlying the graph.