notation: natural numbers = 0,1, 2, 3, 4, 5, ....., (some define it without the zero, though) <= means smaller than or equal to, {} is set notation and means a set of numbers : (such that) then some condition. For example {x: x is not a duck} is the set of all things not a duck. Our goal is to prove that there are 21 different times. let x1 = hours, x2 = tens of minutes, x3 = minutes. We are going to prove the statement about the set {x1, x2,x3: 1<=x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. It will be taken by assumption that this set is the set of digital clock combinations that add up to 6. So then, we must prove that there are unique 21 elements in the set {x1 + x2 + x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. {x1 , x2 , x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6} = {x1 , x2 , x3 : 1<= x1 <= 6, 0<= x2<=5, 0<=x3 <= 5, x1 + x2 + x3 = 6} because x3<=6, and because if x1 >=1, then x2 + x3 <=5, and x3, x2 >= 0 , so surely x3, x2 <= x5. Either x1 = 1, 2, 3, 4, 5, or 6. Next, x1 + x2 + x3 = 6, so x2 + x3 = 6 - x1. There are n+1 natural numbers between 0 and n (I'm being lazy and not proving this, but the proof would be so much longer if I proved it), and since 0 <= x2 <= 5 <= 6-x1, there are at most 6-x1+1 values of x2 for each value of x1. When x1 = 1, there are a maximum of 6, when x1 = 2, there are 6-2+1 = 5, when x1 = 3, there are 6-3+1 = 4, when x1 = 3, there are 3, then 2, and then 1. Summing this up gives us a maximum of 21. So it is at most 21 and at least 21, so exactly 21.
x²+6x+9=49 x²+6x-40=0 x1=-6/2 - Square root of ((6/2)²+40) x1=-3 - 7 x1= -10 x2=-6/2 + Square root of ((6/2)²+40) x2=-3 + 7 x2= 4
The answer depends on absolute deviation from what: the mean, median or some other measure. Suppose you have n observations, x1, x2, ... xn and you wish to calculate the sum of the absolute deviation of these observations from some fixed number c. The deviation of x1 from c is (x1 - c). The absolute deviation of x1 from c is |x1 - c|. This is the non-negative value of (x1 - c). That is, if (x1 - c) ≤ 0 then |x1 - c| = (x1 - c) while if (x1 - c) < 0 then |(x1 - c)| = - (x1 - c). Then the sum of absolute deviations is the above values, summed over x1, x2, ... xn.
The slope is (y2 - y1)/(x2 - x1) That is in this case (-6 + 6)/(4 +4) = 0/8 = 0
The midpoint is going to have an x and y value halfway between those of the two endpoints. The midpoint has an x value 6 higher than the first endpoint and a y value 4 lower. Just continue this pattern to get the other endpoint. (-2+6, 6-4)=(4, 2) The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2] By substituting the given values into the formula we have: (x1 + -8)/2 = -2 and (y1 + 10)/2 = 6 x1 - 8 = -4 and y1 + 10 = 12 x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10 x1 = 4 and y1 = 2 Thus, the other endpoint is (4, 2).
If the variables are x1 & x2 the solution is : 1) x1=x1+x2; 2) x2=x1-x2; 3) x1=x1-x2; EX: x1=1 , x2=6; 1) x1= 1+6 = 7 2) x2= 7-6 =1 3 x1=7-1 =6 ============================================
notation: natural numbers = 0,1, 2, 3, 4, 5, ....., (some define it without the zero, though) <= means smaller than or equal to, {} is set notation and means a set of numbers : (such that) then some condition. For example {x: x is not a duck} is the set of all things not a duck. Our goal is to prove that there are 21 different times. let x1 = hours, x2 = tens of minutes, x3 = minutes. We are going to prove the statement about the set {x1, x2,x3: 1<=x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. It will be taken by assumption that this set is the set of digital clock combinations that add up to 6. So then, we must prove that there are unique 21 elements in the set {x1 + x2 + x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. {x1 , x2 , x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6} = {x1 , x2 , x3 : 1<= x1 <= 6, 0<= x2<=5, 0<=x3 <= 5, x1 + x2 + x3 = 6} because x3<=6, and because if x1 >=1, then x2 + x3 <=5, and x3, x2 >= 0 , so surely x3, x2 <= x5. Either x1 = 1, 2, 3, 4, 5, or 6. Next, x1 + x2 + x3 = 6, so x2 + x3 = 6 - x1. There are n+1 natural numbers between 0 and n (I'm being lazy and not proving this, but the proof would be so much longer if I proved it), and since 0 <= x2 <= 5 <= 6-x1, there are at most 6-x1+1 values of x2 for each value of x1. When x1 = 1, there are a maximum of 6, when x1 = 2, there are 6-2+1 = 5, when x1 = 3, there are 6-3+1 = 4, when x1 = 3, there are 3, then 2, and then 1. Summing this up gives us a maximum of 21. So it is at most 21 and at least 21, so exactly 21.
x²+6x+9=49 x²+6x-40=0 x1=-6/2 - Square root of ((6/2)²+40) x1=-3 - 7 x1= -10 x2=-6/2 + Square root of ((6/2)²+40) x2=-3 + 7 x2= 4
x1/6 = 6√x
Aaron Poison/Bug x1 Bug/Fighting x1 Bug/Flying x2 Poison/Dark x1 Bertha Water/Ground x2 Ground x1 Rock x1 Rock/Ground x1 Flint Fire x1 Fire/Fighting x1 Steel/Ground x1 Normal x1 Ghost/Flying x1 Lucian Psychic x2 Normal/Psychic x1 Fight/Psychic x1 Steel/Psychic x1 Cynthia Ghost/Dark x1 Dragon/Ground x1 Water/Ground x1 Water x1 Grass/Poison x1 Steel/Fighting x1
monsters(19) 1.prime material dragon x2 2.the creator x2 3.cyber dragon x1 4.freed the brave wanderer x2 5.zaborg the thunder monarch x3 6.copycat x1 7.reflect bounder x1 8.skelengel x2 9.morphing jar x1 10.marshmallon x1 11.d.d. warrior lady x1 12.the creator incarnate x2 spelles(17) 1.card of safe return x3 2.heavy storm x1 3.monster reborn x1 4.reinforscment of the army x3 5.enemy controller x1 6.fissure x1 7.smashing ground x1 8.mystical space typhoon x1 9.foolish burrial x2 10.shrink x2 11.lightning vortex x1 12.monster reincarnation x1 traps(5) 1.solmen judgment x3 2.mirror force x1 3.torrential tribute x1
1/6 x 1/6 x1/6 = 1/216
f(x1) = (-5)2 + 3*(-5) + 5.1 = 25 - 15 + 5.1 = 15.1 f(x2) = (6)2 + 3*(6) + 5.1 = 36 + 18 + 5.1 = 59.1 f(x2)-f(x1) = 59.1 - 15.1 = 44 x2 - x1 = 6 - (-5) = 11 So average rate of change = 44/11 = 4
decklist monsters:21 blue eyes white dragon x3 chaos necromancer x1 masked dragon x1 armed dragon lvl3 x2 armed dragon lvl5 x2 armed dragon lvl7 x1 armed dragon lvl10 x1 the dragon dwelling in the cave x1 flamvell guard x1 lord of d x1 vangaurd of the dragon x1 the white stone of legend x1 kaiser sea horse x1 montage dragon x1 mirage dragon x1 tyrant dragon x1 blue eyes shining dragon x1 spell cards:15 flute of summoning dragon x1 polermyzation x2 monster reborn x1 magical mallet x1 stamping destruction x2 dragons mirror x1 deifferent dimension capsule x2 dark hole x1 future fusion x1 white dragon ritual x1 swords of revealing light x1 mystical space typhoon x1 traps:10 dragons rage x1 waboku x1 enchanted javelin x1 judgment of Anubis x1 call of the haunted x1 acid trap hole x1 hidden book of spell x1 raigeki break x1 curse of Anubis x1 self destruction button x1 (hoping i wont need that anymore) extra deck:2 paladin of white dragon x1 blue eyes ultimate dragon x1
we have the points (3,4) and (8,-6) let x1=3 y1=4 x2=8 y2=-6 slope=(y2-y1)/(x2-x1) =(-6-4)/(8-3) =-10/5 =-2
we have the points (3,4) and (8,-6) let x1=3 y1=4 x2=8 y2=-6 slope=(y2-y1)/(x2-x1) =(-6-4)/(8-3) =-10/5 =-2
Mine is: Blizzard Dragon X2 Ryu Kushin Powered X1 Baby Dragon X3 Time Wizard X4 Manga Ryu-Ran X1 Ryu-Ran X1 Armored Lizard X1 Influence Dragon X1 Powered Tuner X2 InterPlanetPurplyThorny Dragon X2 Hieratic Dragon of Eset X1 Light And Darkness Dragon X1 Lord Of D. X1 Koumori Dragon X1 Curse Of Dragon X1 Dragon Of Ice X2 The Dragon Dwelling In the Cave X2 Lava Dragon X1 Two Headed Behemoth X1 Dragunity Arma Mystletainn X1 Hieratic Dragon Of Nebthet X1 Ancient Dragon X1 Dragon Zombie X1 Mirage Dragon X1 Bright Star Dragon X1 Dark Blade X1 Pitch Dark Dragon X1 (I actually have the cards below) MALEFIC CYBER END DRAGON X1 Slifer The Sky Dragon X2 Magic & Traps Card DesctructionX1 Double Summon X1 Gracious Charity X1 Frontline Base X1 reversal quiz X2 MetaSilver Armor X1 Dian Keto The Cure Master X1 Poison Of the old man X1 Dragon Mastery x1 Dragon treasure x1 Fusion Gate x1 change of heart x1