The slope for these two points is undefined, or straight up.
-3,5 and 6,-1
The slope is [2 - (-4)]/[-6 -2] = 6/-8 = -3/4
The slope is [-4 - (-2)]/[6 - 3] = [-4 + 2]/[6 - 3] = -2/3
Points: (-2, 4) and (-6, 12) Slope: -2
(3--4)/2--6) = 7/8 which is the slope of the line.
Points: (6, -4) and (3, 4) Slope: -8/3
Points: (2, 6) and (-3, -4) Slope: 2
Points: (2, 6) and (-3, -4) Slope: 2
Points: (6, 4) and (6, 8)Slope: 0 because it is a vertical straight line that is parallel to the y axis
The slope for these two points is undefined, or straight up.
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
If you mean points of (3, 4) and (-6, 10) then the slope is -2/3
The slope, m, of a line given 2 points is: (y2 - y1) / (x2 - x1). m = (-6 - (-9)) /(3-(-4)) or 3/7. Therefore parallel line slope is 3/7.
Points: (0, 0) and (-5, -6) Slope: 6/5
Let (x1, y1) = (0, 6) and (x2, y2) = (4, 0), then slope = m = (y2 - y1)/(x2 - x1) m = (0 - 6)/(4 - 0) = -6/4 = -3/2 Thus, the slope of a line that passes though points (0, 6) and (4, 0) is -3/2.
-3,5 and 6,-1