The GCF is y4
4x-y4 what = 0
√x7 = (x7)1/2 = x7/2 ≡ x3.5
sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5
what d\oes a x7 stand fotr.
The GCF is y4
x=y4 /2
4x-y4 what = 0
√x7 = (x7)1/2 = x7/2 ≡ x3.5
The simplest equation would be y4 = 0
(x2 + y2)(x + y)(x - y) = x4 - y4.
sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5
It will fit both of them.
what d\oes a x7 stand fotr.
-2
y + y4 = y5 , possibly. Except that conventionally, the number (or coefficient) would be written first. y + y4 = y*(1 + y3) = y(1 + y)*(1 - y + y2)
y4