solving for the x variable given that x2-6x+5=0
factoring the polynomial gives (x-1)(x-5)=0 which leaves you with your two answers, x=1, 5
or you could have used the quadratic equation
x = [ -(-6) plus/minus sqrt( (-6)2 - 4*1*5 ) ] / (2*1)
x = [ 6 plus/minus sqrt( 36-20 ) ] / 2
x = [ 6 plus/minus 4 ] / 2
x = 3 plus/minus 2
x = 5, 1
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
15z+5+6z=0 21z+5=0 z=-5/21
The answer to the equation 9 plus 5 times 0 equals 45. This was taught in 5 grade math.
x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
The equation you are looking for is x + 5 = 0. To solve for x, you would subtract 5 from both sides of the equation. This would give you x = -5. Therefore, -5 plus 5 equals 0.
0. Any equation that has times 0 equals 0.
a = 0
5
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
-5
x=0
15z+5+6z=0 21z+5=0 z=-5/21
(1, 0)
No.
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
the answer is 0