1.5
sin x = √3/2
x = sin-1 √3/2
x = 60
1.5
It would be 1 over square root 5.
square root 3/2
-cos(x) + constant
It is not totally clear to what the square root applies*; if just the 2, then: d/dx ((√2)sin x) = (√2) cos x if all of 2 sin x, then: d/dx (√(2 sin x)) = cos x / √(2 sin x) * for the second version I would expect "square root all of 2 sin x" but some people would write as given in the question meaning this, so I've given both just in case.
cos A=3/5 sin=square root of (1-cos2) sin=square root of (1-3/52) sin=square root of (1-9/25) sin=square root of (16/25) sin=4/5 csc=1/sin csc=1/(4/5) csc=5/4
sin(405) = square root of 2 divided by 2 which is about 0.7071067812
2.5
750
1.5
one over the square root of 2 or 0.850903525
It would be 1 over square root 5.
sin-30 = (-1) x 1/(square root of 2) -sin30 = -(1/square root of 2) They are equal
The answer to the math question Cos 5t cos 3t -square root 3 2 - sin 5t cos 3t equals 0. In order to find this answer you will have to find out what each letter is.
The derivative of cos x is -sin x, the derivative of square root of x is 1/(2 root(x)). Applying the chain rule, the derivative of cos root(x) is -sin x times 1/(2 root(x)), or - sin x / (2 root x).
square root 3/2
1/square root 2