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If angle A is 60 degrees angle B is 45 degrees angle C is 75 degrees and the length of side AC is 10 units then what is the length of side AB?
This problem can be solved using the Sine Rule :a/sin A = b/sin B = c/sin C 10/sin 45 = AB/sin 75 : AB = 10sin 75 ÷ sin 45 = 13.66 units (2dp)
What is the value of sin60?
sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
What is x if the Sin of x equals square root 3 divided by 2?
1.5
What is the supplement of 120 degrees?
60 degrees
The shorter leg of a 30-60-90 degree triangle is 6 what is the length of the other leg?
Use the Sine rule. If L is the length of the longer leg, then L/sin(60) = 6/sin(30) So that L = 6*sin(60)/sin(30) = 12*sin(60) = 12*sqrt(3)/2 = 10.39 units.
What is the tangent of 60 degrees?
Tan(60) = Sin(60)/ Cos(60) Sin(60) = sqrt(3)/2 Cos(60) = 1/2 Hence Sin(60) / Cos(60) = [sqrt(3) / 2] / [1/2} => sqrt(3) / 2 X 2/1 sqrt(3) Hence Tan(60) = sqrt(3) = Numerically = 1.732050808....
Find the value of sin 300 degrees?
sin 300 = -sin 60 = -sqrt(3)/2 you can get this because using the unit circle.
How do you get angle size of a 60 feet multiply 90 feet?
5400
Solve sin x square root of 3 by 2?
Do you mean sin(x)=sqrt(3)/2? IF so, look at at 30/60/90 triangle. We see the sin 60 degrees is square (root of 3)/2
Why is sine 30 the same as cosine of 60?
sin(30) = sin(90 - 60) = sin(90)*cos(60) - cos(90)*sin(60) = 1*cos(60) - 0*sin(60) = cos(60).
If angle A is 60 degrees angle B is 45 degrees angle C is 75 degrees and the length of side AC is 10 units then what is the length of side AB?
This problem can be solved using the Sine Rule :a/sin A = b/sin B = c/sin C 10/sin 45 = AB/sin 75 : AB = 10sin 75 ÷ sin 45 = 13.66 units (2dp)
What is the value of sin60?
sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
What is the sin 60?
sin 60 = √(3)/2 or about 0.866 ■
What is sin 57 degrees?
The sine of 57 degrees is approximately 0.8387.
What is sin 97 degrees?
all sin is sin97 degrees Fahrenheit = 36.1 degrees Celsius
Sin equals 0.9?
Sin(X) = 0.9 X = Sin^(-1) 0.9 X = 64.158... degrees.
What is the sin of 105 degrees?
sin 105 = sin (60+45) = sin60cos45 + cos60sin45sin 105 = ((sqrt(3)/2)((sqrt(2)/2)) + ((1/2)((sqrt(2)/2)))sin 105 = (sqrt(6) + sqrt(2)) / 4
