square root 3/2
This problem can be solved using the Sine Rule :a/sin A = b/sin B = c/sin C 10/sin 45 = AB/sin 75 : AB = 10sin 75 ÷ sin 45 = 13.66 units (2dp)
sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
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60 degrees
Use the Sine rule. If L is the length of the longer leg, then L/sin(60) = 6/sin(30) So that L = 6*sin(60)/sin(30) = 12*sin(60) = 12*sqrt(3)/2 = 10.39 units.
sin 300 = -sin 60 = -sqrt(3)/2 you can get this because using the unit circle.
5400
Do you mean sin(x)=sqrt(3)/2? IF so, look at at 30/60/90 triangle. We see the sin 60 degrees is square (root of 3)/2
sin(30) = sin(90 - 60) = sin(90)*cos(60) - cos(90)*sin(60) = 1*cos(60) - 0*sin(60) = cos(60).
This problem can be solved using the Sine Rule :a/sin A = b/sin B = c/sin C 10/sin 45 = AB/sin 75 : AB = 10sin 75 ÷ sin 45 = 13.66 units (2dp)
sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
sin 60 = √(3)/2 or about 0.866 ■
The sine of 57 degrees is approximately 0.8387.
all sin is sin97 degrees Fahrenheit = 36.1 degrees Celsius
Sin(X) = 0.9 X = Sin^(-1) 0.9 X = 64.158... degrees.
sin 105 = sin (60+45) = sin60cos45 + cos60sin45sin 105 = ((sqrt(3)/2)((sqrt(2)/2)) + ((1/2)((sqrt(2)/2)))sin 105 = (sqrt(6) + sqrt(2)) / 4
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