x2_12x-3 = 0
Using the formula for solving quadratics:
x = 12 plus/minus sqrt (144 - (4 x 1 x -3))/2
x = 12 plus/minus (sqrt 156)/2
x = 12 + (sqrt 156)/2 = 12.25
or x = 12 - (sqrt 156)/2 = -0.25
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By factoring I get x-3 divided by x+3
-3
(x+3)(x-3)
If you mean: 9x squared-12x+4 when x = 3 Then it is: (9*3*3)-(12*3)+4 = 49
(x-3)(3x+1)