x2_12x-3 = 0
Using the formula for solving quadratics:
x = 12 plus/minus sqrt (144 - (4 x 1 x -3))/2
x = 12 plus/minus (sqrt 156)/2
x = 12 + (sqrt 156)/2 = 12.25
or x = 12 - (sqrt 156)/2 = -0.25
By factoring I get x-3 divided by x+3
-3
(x+3)(x-3)
If you mean: 9x squared-12x+4 when x = 3 Then it is: (9*3*3)-(12*3)+4 = 49
(x-3)(3x+1)
x^(3) - x^(2) - 12x 'x' is a common fractor ' tsker it out. Hence x(x^(2) - x - 12) Factor inside the brackets / x(x - 4(x + 3) Done!!!!!
2(x - 3)(x - 3)
2x^(3) - 10x^(2) - 12x '2' and 'x' are common factors , so take them out. Hence 2x(x^(2) - 5x - 6) Factor inside the brackets . 2x(x - 6)(x + 1) Done !!!!
4x + 20
4x2+12x = 4x(x+3) when factored
(75y - 12x^2) * y = 75y^2 -12x^2y 75y - (12x^2 * y) = 75y -12x^2y
x - 2
By factoring I get x-3 divided by x+3
x + 1
It is x^2 + 12x or x(x + 12).
-3
x2 - 12x + 36 = (x - 6)2