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x2_12x-3 = 0

Using the formula for solving quadratics:

x = 12 plus/minus sqrt (144 - (4 x 1 x -3))/2

x = 12 plus/minus (sqrt 156)/2

x = 12 + (sqrt 156)/2 = 12.25

or x = 12 - (sqrt 156)/2 = -0.25

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15y ago

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