sqrt x9 = x9/2 = x4.5------This depends on what you're asking. If you're asking sqrt(9x), or square root of "9" times "x", then the answer would be 3(sqrt(x)), or 3 times square root of x.If you were asking sqrt(x^9), then the answer would be as follows:sqrt(x^9)= sqrt((x^8)*(x))= [sqrt(x^8)]*[sqrt(x)]= (x^4)*(sqrt(x))(If it's too hard to understand, the answer would be x^4 times the square root of x.)That was simplified radical form. The above answer, x^(4.5) is also correct.
y = sqrt X + 3sqrt X is the same as y = 4 sqrt X
sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5sqrt(x7) = sqrt(x6*x) = x3*sqrt(x)or, more simply,sqrt(x7) = x7/2 = x3.5
You rationalize denominators by using a form of one. Thus. sqrt(X + 6)/sqrt(X) * sqrt(X)/sqrt(X) = sqrt(X2 + 6X)/X ------------------------
-24 = 4 x 6 x -1 Sqrt -24 = sqrt 4 x sqrt 6 x sqrt -1 = 2 x sqrt 6 x i = 2i root6
sqrt( x13 ) = sqrt ( x12 times x ) = sqrt ( x12 ) times sqrt( x ) = x6 times sqrt( x ).
SQRT(X) * SQRT(X) = X
Notice that 720 = (4 x 5 x 36)sqrt(720) = sqrt(4 times 5 times 36)= sqrt(4) times (sqrt(5) times sqrt(36)= (2) times sqrt(5) times (6)= 12 sqrt(5)
sqrt(6) x sqrt(24) =sqrt(6) x sqrt(6 x 4) = sqrt(6) x sqrt(6) x sqrt(4) = sqrt(6) x sqrt(6) x 2 = 6 x 2 =12
sqrt(3) x sqrt(15) = sqrt( 3 x 15 ) = sqrt( 45 ) = sqrt( 9 x 5 ) = 3 sqrt(5)
sqrt x9 = x9/2 = x4.5------This depends on what you're asking. If you're asking sqrt(9x), or square root of "9" times "x", then the answer would be 3(sqrt(x)), or 3 times square root of x.If you were asking sqrt(x^9), then the answer would be as follows:sqrt(x^9)= sqrt((x^8)*(x))= [sqrt(x^8)]*[sqrt(x)]= (x^4)*(sqrt(x))(If it's too hard to understand, the answer would be x^4 times the square root of x.)That was simplified radical form. The above answer, x^(4.5) is also correct.
sqrt(8) x sqrt(32) = sqrt(8 x 32) = sqrt(256) = 16
sqrt 175 = sqrt 25 x sqrt 7 = 5 x sqrt 7
y = sqrt X + 3sqrt X is the same as y = 4 sqrt X
Multiplying the radicands of the two together, sqrt(2) x sqrt(15) is equal to sqrt(2 x 15) = sqrt(30).
Suppose the number is x then [6x - sqrt(5)]/x = 1 so 6x - sqrt(5) = x or 5x = sqrt(5) x = sqrt(5)/5 = sqrt(5)
3 sqrt(6) x sqrt(6) = 18