You rationalize denominators by using a form of one. Thus.
sqrt(X + 6)/sqrt(X) * sqrt(X)/sqrt(X)
= sqrt(X2 + 6X)/X
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Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
If you want to rationalize the denominator, then multiply numerator & denominator by sqrt(5), so 8*sqrt(5)/5 = approx 3.578
It is called rationalizing the denominator, and it is done by multiplying numerator and denominator by appropriate numbers. Note that if you do that, you will usually end up with radicals in the numerator. Examples: 1 / (square root of 2): Multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3): Multiply numerator and denominator by (square root of 2 - square root of 3).
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Yes, the expression 2 divided by 2 square root 3 can be simplified. To simplify this expression, we need to rationalize the denominator. Multiplying both the numerator and the denominator by the conjugate of the denominator (2 square root 3), we get (2 * 2 square root 3) / (2 * 2 square root 3 * 2 square root 3). This simplifies to 4 square root 3 / 12, which further simplifies to square root 3 / 3.
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
You cannot. The square root of 5 is irrational.
Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
It looks like your question is [1-sqrt(3)] / [1+sqrt(3)], and you want to rationalize the denominator. If this is the case, multiply both numerator and denominator by (1-sqrt(3)), and get for the denominator = -2, and the numerator = 4 - 2*sqrt(3), so the answer is sqrt(3) - 2
An example may help. If you have the fraction 1 / (2 + root(3)), where root() is the square root function, you multiply top and bottom by (2 - root(3)). If you multiply everything out, you will have no square root in the denominator, instead, you will have a square root in the numerator. If the denominator is only a root, eg root(3), you multiply top and bottom by root(3).
If you want to rationalize the denominator, then multiply numerator & denominator by sqrt(5), so 8*sqrt(5)/5 = approx 3.578
4=(sqrt2)4
(2√24) / √54 = (2√4√6) / (√9√6) = (4√6)/(3√6) = 4/3
It is called rationalizing the denominator, and it is done by multiplying numerator and denominator by appropriate numbers. Note that if you do that, you will usually end up with radicals in the numerator. Examples: 1 / (square root of 2): Multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3): Multiply numerator and denominator by (square root of 2 - square root of 3).
Depends on the situation. You usually have to multiply numerator and denominator by some number or expression. Examples: 1 / square root of 2 Here, you have to multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3) Here, you have to multiply numerator and denominator by (square root of 2 - square root of 3).
Of course you can. You can have a square root anywhere it needs to be to get the correct answer!
find the square root of the numerator and the square root of the denominator