10.2
Multiple of 4 less than 15
It is greater by 6.6
989. If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3. If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5. Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15). So what is needed is an even multiple of 15 less than or equal to 1000: 1000 ÷ 15 = 662/3 Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.
Smallest multiple of 7 greater than 100 is 15 Largest multiple of 7 less than 1000 is 142 So number of multiples of 7 = 142 - 15 + 1 = 128
9 and 15
510. To be divisible by 3, it must be a multiple of 3. Thus the required number is a multiple of both 3 and 5, which will be a multiple of their lcm: lcm(3, 5) = 15. → 495 ÷ 15 = 33 → first multiple of 15 greater than 495 is 15 x 34 = 510 → 525 ÷ 15 = 35 → last multiple of 5 less than 525 is 15 x 34 x 510 → number required is 510.
.15 is less than .6 is.
-15 is less than 12
10.2
Multiple of 4 less than 15
It is greater by 6.6
989. If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3. If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5. Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15). So what is needed is an even multiple of 15 less than or equal to 1000: 1000 ÷ 15 = 662/3 Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.
Any negative number would be less than any positive number. So that would make -15 less than 5, by -20.
No because 11 is greater than -15
178 mm = 17.8 cm which is greater than 15 cm
Smallest multiple of 7 greater than 100 is 15 Largest multiple of 7 less than 1000 is 142 So number of multiples of 7 = 142 - 15 + 1 = 128