22
2 and 4
If: 6x+8 = 32 Then: x = 4
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
Sum the number and divide the answer by the number of values that were added together.
22
The fourth number is 8.
Positive 29.... -21 + 29 = 8
36
2 and 4
403Γ·8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor Γquotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
If: 6x+8 = 32 Then: x = 4
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
Assuming that the given number is 5/6, the other must be 7 1/6.
13
+6: Oxygen in oxyanions is assumed to have an oxidation state of -2; there are four such oxygen atoms, for a total of -8, and the SO4 anion has a charge of -2. This means that the sulfur atom must have an oxidation state of +6, because +6 added to - 8 = -2.
Sum the number and divide the answer by the number of values that were added together.