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What number must be added to 6 16 and 8 to get an average of 13?
22
What number must be added to -19 to get -11?
To find the number that must be added to -19 to get -11, you can set up the equation: -19 + x = -11. Solving for x, you add 19 to both sides, resulting in x = -11 + 19, which simplifies to x = 8. Therefore, the number that must be added to -19 is 8.
What are the numbers if the number added to 8 times the numbers reciprocal is 6?
2 and 4
What is the smallest number which must be added to 403 to make it divisible by 8?
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
What is the equation for If 6 times a certain number is added to 8 the result is 32?
If: 6x+8 = 32 Then: x = 4
What number must be added to 6 16 and 8 to get an average of 13?
22
In the collection 10 and 8and 6 what number can be added so the mean is 8?
The fourth number is 8.
What number must be added to -21 to get positive 8?
Positive 29.... -21 + 29 = 8
What number must be added to -19 to get -11?
To find the number that must be added to -19 to get -11, you can set up the equation: -19 + x = -11. Solving for x, you add 19 to both sides, resulting in x = -11 + 19, which simplifies to x = 8. Therefore, the number that must be added to -19 is 8.
When 6 is added three times a number the result is 30. find the number?
36
What are the numbers if the number added to 8 times the numbers reciprocal is 6?
2 and 4
What is the smallest number which must be added to 403 to make it divisible by 8?
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
Find the smallest number which must be added to 403 to make it exactly disvivible by 8?
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
What is the equation for If 6 times a certain number is added to 8 the result is 32?
If: 6x+8 = 32 Then: x = 4
What number has a remainder of 1 when divided by 6 and a remainder of 2 when divided by 8?
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
The sum of two rational number is 8 ifone of the number is 5 6 find other?
Assuming that the given number is 5/6, the other must be 7 1/6.
What must be added -5 to get 8?
13
