It is 3823.
To solve this problem, we need to break down the number into its place values. Let's denote the number as ABCD, where A is the thousands place, B is the hundreds place, C is the tens place, and D is the ones place. From the given information, we can form the following equations: B = A - 4, C = A + 1, and D = B + 5. By substituting the first equation into the second and third equations, we get C = (B + 4) + 1 = B + 5. Therefore, the number is 6953.
From AAA math:Numbers, such as 495,784, have six digits. Each digit is a different place value.The first digit is called the hundred thousands' place. It tells you how many sets of one hundred thousand are in the number. The number 495,784 has four hundred thousands.The second digit is the ten thousands' place. In this number there are nine ten thousands in addition to the four hundred thousands.The third digit is the one thousands' place which is five in this example. Therefore there are four sets of one hundred thousand, nine sets of ten thousand, and five sets of one thousand in the number 495,784.The fourth digit is called the hundreds' place. It tells how many sets of one hundred are in the number. The number 495,784 has seven hundreds in addition to the thousands.The next digit is the tens' place. This number has are eight tens in addition to the four hundred thousands, nine ten thousands, five thousands and seven hundreds.The last or right digit is the ones' place which is four in this example. Therefore there are four sets of one hundred thousand, nine sets of ten thousand, five sets of one thousand, seven sets of one hundred, eight sets of ten, and four ones in the number 495,784.
The 6s in the number 7,664 are in the hundred and the tenth spot.
5 is in the thousands position. the 3 to the left is in hundreds. the 6 is in the tens position. the second 3 is in the units position. the 4 is in the tenths position
Oh, dude, rounding 2465 to the nearest thousands is like, super easy. You just look at the hundreds place, which is 4, and since it's less than 5, you keep the thousands place as it is. So, 2465 rounded to the nearest thousands is 2000. Easy peasy, lemon squeezy.
The relationship between the 6's in the number is the first 6 is the thousands digit and the second 6 is the hundreds digit.
The relationship between the 6's in the number is the first 6 is the thousands digit and the second 6 is the hundreds digit.
The first 6 in the number is in the thousands place (6,000), and the second 6 is in the hundreds place (600).
No. You could say Hundreds of thousands. The first # must be smaller than the second #.
One thousand, eight hundred and seven. The first number is the thousands, the second number is the hundreds, the third number is the tens (since its 0, there are none)
To write a six-digit number with the 5 in the ten thousands place and the 2 in the ones place, you can start by placing the 5 in the second digit from the left (the ten thousands place). Then, place the 2 in the far right position (the ones place). You can fill the remaining digits (hundreds of thousands, thousands, and hundreds) with any digits, including zeros, to complete the number. For example, a possible number could be 500,042.
In the number 4498, the two '4's are in the thousands and hundreds places, respectively. They share the same value, contributing a total of 8000 to the overall value of the number. This repetition emphasizes the significance of the thousands place in determining the magnitude of the number, while the second '4' reinforces its value in the hundreds place. Thus, the relationship between the two '4's is one of positional value within the number.
To solve this problem, we need to break down the number into its place values. Let's denote the number as ABCD, where A is the thousands place, B is the hundreds place, C is the tens place, and D is the ones place. From the given information, we can form the following equations: B = A - 4, C = A + 1, and D = B + 5. By substituting the first equation into the second and third equations, we get C = (B + 4) + 1 = B + 5. Therefore, the number is 6953.
In the number 8800, the first 8 is in the thousands place, giving it a place value of 8,000. The second 8 is in the hundreds place, so its place value is 800. Together, these 8s contribute to the overall value of the number.
3. Split the number into blocks of 3 digits from the right hand end (34 816). Then in each block, the digits are H-T-U = Hundreds-Tens-Units. From the right hand end the blocks are "none", "Thousands", "Millions", ... So the ten thousands place is the tens digit (second from right hand end of the block) of the thousands block (second from the right hand end): thousands.......none .... HTU............ HTU ........34............. 816 Ten-thousands digit = 3.
A second is a length of time, while a hertz is a unit of frequency, so you can have as many hertz in a second as you want. therefore it depends on what frequency you are talking about, as you can have hundreds of thousands of hertz per second.
The current machines are in the billions. They have come out with RISC chips that only do thousands per second.