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To solve this problem, we need to break down the number into its place values. Let's denote the number as ABCD, where A is the thousands place, B is the hundreds place, C is the tens place, and D is the ones place. From the given information, we can form the following equations: B = A - 4, C = A + 1, and D = B + 5. By substituting the first equation into the second and third equations, we get C = (B + 4) + 1 = B + 5. Therefore, the number is 6953.

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11y ago
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Q: What number has 8 thousand 4 fewer hundreds than thousands 1 more tens than thousands and 5 more ones than hundreds?
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