There are 24 numbers between 1 and 100 that are divisible by four: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, and 100.
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To find the total number of integers between 100 and 300 that are divisible by 3, we first determine the smallest and largest integers in this range that are divisible by 3. The smallest integer divisible by 3 is 102, and the largest is 297. To find the total number of integers between 102 and 297 that are divisible by 3, we calculate (297-102)/3 + 1, which equals 66. Therefore, there are 66 integers between 100 and 300 that are divisible by 3.
There are 49 numbers between 1 and 100 that are divisible by two.
33 numbers between 1 and 100 are divisible by 3.
There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.
The first whole number divisible by 3 is 102 and the last one 399. Let n be the number of whole numbers between 102 and 399 102 + (n - 1)x3 = 399 (this is an arithmetic progression) Solving n, n-1 = (399 - 102)/3 = 99 n = 100 Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50. regards, lpokbeng