1 only as 3 & 5 r prime numbers.
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The number that is between 40 and 50 and is divisible by both 3 and 5 is 45. To determine if a number is divisible by both 3 and 5, you must ensure it is divisible by both 3 and 5 without leaving a remainder. In this case, 45 meets this criteria as it is divisible by both 3 (45 ÷ 3 = 15) and 5 (45 ÷ 5 = 9).
It is: 1
15
5 and 1 both go into 10 and 5.
'15' Hence 3 x 5 = 15 or 15/3 = 5 or 15/5 = 3